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2 years ago

What's the median of 42, 43, 42, 37, 41, 44, 45

Mathematics

2 answers:

Julli [10]2 years ago

5 0

Answer: 42

Step-by-step explanation: The median is the middle number in the data set when the data set is written from least to greatest.

So let's write our data set from least to greatest.

We have 37, 41, 42, 42, 43, 44, 45.

Now we can see that the middle number is 42.

I have underlined the digit above.

So the median is 42.

solmaris [256]2 years ago

3 0

Answer:

Step-by-step explanation:

Organize the numbers from least to greatest

37, 41, 42, 42, 43, 44, 45

Find the number in the middle

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The length of a rectangle is 3ft less than double the width, and the area of the rectangle is 14ft^2 find the dimensions of rect

german

Answer: $4\times 3.5\ ft^2$

Step-by-step explanation:

Given

area of the rectangle is $A=14\ ft^2$

Suppose width is given by w

So, length is $l=2w-3$

The area of a rectangle is $A=l\times w$

putting values

$\Rightarrow A=(2w-3)w\\\Rightarrow 14=2w^2-3w\\\Rightarrow 2w^2-3w-14=0\\\Rightarrow 2w^2-7w+4w-14=0\\\Rightarrow w(2w-7)+2(2w-7)=0\\\Rightarrow (2w-7)(w+2)=0\\\\\Rightarrow w=\dfrac{7}{2}\ ft$

length is $l=4\ ft$

6 0

2 years ago

I really need an answer pls I used all my points :’(

Mazyrski [523]

Answer:

266 tickets

Step-by-step explanation:

Ratio of adult tickets to child tickets is 4 : 3

So, if we think of these as "parts", there are 4 parts adult tickets and 3 parts child tickets.

In total there is:

4 + 3 = 7 parts

Now, given 152 adult tickets. If there are 4 parts of adult tickets, how much is each part worth?

152/4 = 38

Total amount of tickets is 7 of these "parts", so total number of tickets is:

38 * 7 = 266 tickets

5 0

3 years ago

Read 2 more answers

Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2

vladimir1956 [14]

Using the normal approximation to the binomial, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem:

15% do not show up, so 100 - 15 = 85% show up, which means that $p = 0.85$ .
300 tickets are sold, hence $n = 300$ .

The mean and the standard deviation are given by:

$\mu = np = 300(0.85) = 255$

$\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185$

The probability that we will have enough seats for everyone who shows up is the probability of at most 270 people showing up, which, using continuity correction, is $P(X \leq 270 + 0.5) = P(X \leq 270.5)$ , which is the p-value of Z when X = 270.5.