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marin [14]
3 years ago
12

8 less than 5 times a number

Mathematics
2 answers:
nignag [31]3 years ago
8 0

Answer:

5x - 8

Step-by-step explanation:

Unable to solve completely.

Arturiano [62]3 years ago
5 0

Answer:

8< 5x

Step-by-step explanation:

We know that the 8 is less than 5 times a number, so we first put 8 <.

From here, we have the value 5 being multiplied by a number, that number can be any variable unless that specifically state which variable to use.

Hope this helps! :)

(Side Note: If you're talking about inequalities this should work, if not then I'm sure others will post different answers.)

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PLEASE ANSWER AND EXPLAIN 99 POINTS [URGENT]
givi [52]

Answer:

A

Step-by-step explanation:

The farther you move through x, the more y decreases

4 0
3 years ago
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What is the product of the binomials below? (3x+6)(4x+2)
RUDIKE [14]

Answer:

7x (times) 8

Step-by-step explanation:

(3x+6)(4x+2)

(3x + 4x)(6 + 2)

7x (times) 8

3 0
3 years ago
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Can someone help me with these two questions?
fenix001 [56]

Answer:

17) A(-1,1) B(-1,4) C(5,1)

18) (From origin moving rightwards)

     A(0,0) B(a, 0) C(a,a) D(0,a)

Step-by-step explanation:

17) You just count the steps, how many steps left, right, up, or down

18) The first point is at the origin, so 0,0

    The second point that lies on the x axis is (a,0) as it is a distance from the origin, 0 because it's on the x-axis.

     The third point is (a,a) because it is a distance to the right of the origin AND a distance upwards from the x axis.

      The fourth point (0,a) because it is on the vertical line (0) and is a distance above the origin.

5 0
2 years ago
Please help, dont understand
Artemon [7]

Answer:

D

Step-by-step explanation:

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3 0
3 years ago
Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p
Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t  

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t  = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

6 0
3 years ago
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