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soldier1979 [14.2K]
3 years ago
5

What is the best approximation of 6% tax on a $102 purchase? A) $6 B) $12 C) $18 D) $24

Mathematics
1 answer:
larisa [96]3 years ago
6 0
Here, On Approximation, Just consider $102 as $100

Then, 6% of 100 would be: $6 

In short, Your Answer would be: Option A

Hope this helps!
You might be interested in
After college you start a job earning $40,000 a year. You get a 6% raise each year.
alex41 [277]
Answers: A) $44,944
B) $50,499.0784


Math: Using the percentage calculator linked below 6% of $40,000 is $2,400. Since you're getting your second raise after your first and since it is a 6% raise from what you're getting paid at that time we add pay raise 1 to your starting pay before calculating the 6% for pay raise 2. $40,000+$2,400=$42,400. 6% of $42,400 is $2,544. $42,400+$2,544=$44,944, Since that is two pay raises that would be your earnings at the end of year two (answer A).
We continue calculating 6% then adding that onto the total before calculating it for the next year for problem B.
6% of $44,944 is $2,696.64. $44,944+$2,696.64=$47,640.64.
6% of $47,640.64 is $2,858.4384. $47,640.64+$2,858.4384=$50,499.0784. That's answer B.


Hopefully you can figure out C on your own! I feel a little bad for giving a partial answer but I think you can do this!

Percentage calculator used-https://percentagecalculator.net/
Note: can't handle commas, remove all commas before entering data in.
7 0
3 years ago
The perfect orange calls for 2/3 parts yellow paint and 1/4 parts red paint.
sergejj [24]
A. 2 2/3

B. 3/8

Hope this helped

8 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
I need help! ill give brainliest! please!
Serggg [28]
How explain please !!!!!!!!!!
4 0
3 years ago
No clue what to do. show all steps too please. thanks. HELP DUE NOW!!!
dangina [55]
An isosceles triangle has two equal sides.
a= one equal side
b=base

b+2a=35
a=b+4
b+ 2(b+4)=35
b+2b+8=35
3b+8=35
3b=27
b=9
a=13
4 0
3 years ago
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