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Andrews [41]
3 years ago
7

The growth of one child is represented by the expression 5x – 1. The growth of a second child is represented by the expression 2

x + 3.
Complete and simplify the expressions to represent the total growth of both children.
Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0

5x-1=2x+3

subtract 2x from both sides.

3x-1=3

add 1 to both sides.

3x=4

3/4 is .75

answer is 3/4

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Solve for z: 11=6|-2z| -5
skad [1K]

Answer:

the roots are {-4/3, 4/3}

Step-by-step explanation:

Begin the solution of 11=6|-2z| -5 by adding 5 to both sides:

11=6|-2z| -5 becomes 16 = 6|-2z|.

Dividing both sides by 12 yields

16/12 = |-z|

There are two cases here:  first, that one in which z is positive and second the one in which z is negative.

If z is positive, 4/3 = -z, and so z = -4/3, and:

If z is negative, 4/3 = z

Thus the roots are {-4/3, 4/3}

3 0
3 years ago
Pre-Calculus Help? Polar and Parametric Equations?
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7 0
3 years ago
3,9,6,9,27,24,27,81,78,81,243,?find out last figure to complete series
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3 years ago
From a point 100 m from a building the angles of elevation of the top and bottom of a flagpole atop a building are 54.5 degrees
AnnZ [28]

Answer:60ft

Step-by-step explanation:The height of the flagpole is approximately  

60

feet.

Explanation:

Always try to draw a diagram.

enter image source here

We know that there is a right angle between the ground and the building. Therefore, we can use the 3 basic trig ratios instead of the sine or cosine law to solve this problem.

Since the angle in the corner of the larger right triangle measures  

42

˚

, the top angle in this triangle measures  

180

˚

−

90

˚

−

42

˚

=

48

˚

.

By basic trig ratios, we can find the height of the building with the flag pole on top, call it  

H

.

tan

42

˚

1

=

H

500

H

=

500

tan

42

˚

I would keep it in exact form until the last step.

We now devise an expression for the height of the building (without the flag pole). Call it  

a

tan

38

˚

1

=

a

500

a

=

500

tan

38

˚

We can now state that

h

=

H

−

a

h

=

500

tan

42

˚

−

500

tan

38

˚

h

≈

59.559

≈

60

feet

Hopefully this helps!

Answer link

EET-AP

Apr 10, 2017

The flagpole is  

60

f

t

in height to the nearest foot.

Explanation:

1) The flagpole is on top of a building.

2)Angles of elevation both measured from point  

500

f

t

from building

3) Angle of elevation to the top of building is  

38

d

e

g

4) Angle of elevation to the top of flagpole is  

42

d

e

g

The information above will provide us with two right angle triangles, one smaller one inside a larger one.

Both will have a base of  

500

f

t

.

The smaller triangle will have a base angle  

β

of  

38

deg opposite the  

90

deg, and the larger triangle will have a base angle  

β

of  

42

deg.

From this information we can find the heights of the building and the building + pole using the definition of the tangent of the two base angles  

β

:

tan

(

β

)

=

o

p

p

a

d

j

where the  

o

p

p

is the height and the  

a

d

j

is the  

500

f

t

o

p

p

(

b

u

i

l

d

)

=

tan

(

38

)

⋅

(

500

f

t

)

=

390.6

f

t

=

height of building

o

p

p

(

f

l

a

g

)

=

tan

(

42

)

⋅

(

500

f

t

)

=

450.2

f

t

=

height of building + pole

Then to the nearest foot the height of the flagpole is:

450.2

f

t

−

390.6

f

t

=

60

f

t

4 0
3 years ago
Can someone help with this one
natali 33 [55]
Since the base is 4x4, and the height is 2, you'll use the 2 as the height of the netting and the 4 as the length. so, it will be 2x4 which is 8ft^2
4 0
3 years ago
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