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Elza [17]
3 years ago
13

Veronica is opening a bakery. She plans to start by selling cakes. It costs her

Mathematics
2 answers:
LekaFEV [45]3 years ago
5 0

Answer:

your  answer is C. C=7.50n+ 570

hope this help  :)

mash [69]3 years ago
4 0
Your answer is C. C=7.50n+ 570
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Marking brianliest pls help
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Answer:

117.3

Step-by-step explanation:

7*4=117.29=117.3

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Step-by-step explanation:

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2 years ago
Read 2 more answers
What is the midpoint of line segment AB?
Elza [17]

Answer

Midpoint = (3, 5.5)

Step by step explanation

Here we have to use the midpoint formula.

Midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} \\)

Here the point A = (-1, 8) and B = (7, 3)

x1 = -1, y1 = 8, x2 = 7 and y2 = 3

Now plug in these values into the formula.

Midpoint = (\frac{-1 + 7}{2} , \frac{8 + 3}{2}

= (6/2, 11/2)

= (3, 5.5)

Therefore, the midpoint the line segment AB is (3, 5.5)

Thank you.


8 0
3 years ago
Read 2 more answers
2y = 4x - 8 <br>3x + 2y = 6<br>graph​
Vinvika [58]

Answer:

  see attached

Step-by-step explanation:

I find it convenient to let a graphing calculator draw the graph (attached).

__

If you're drawing the graph by hand, there are a couple of strategies that can be useful.

The first equation is almost in slope-intercept form. Dividing it by 2 will put it in that form:

  y = 2x -4

This tells you that the y-intercept, (0, -4) is a point on the graph, as is the point that is up 2 and right 1 from there: (1, -2). A line through those points completes the graph.

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The second equation is in standard form, so the x- and y-intercepts are easily found. One way to do that is to divide by the constant on the right to get ...

  x/2 +y/3 = 1

The denominators of the x-term and the y-term are the x-intercept and the y-intercept, respectively. If that is too mind-bending, you can simply set x=0 to find the y-intercept:

  0 +2y = 6

  y = 6/2 = 3

and set y=0 to find the x-intercept

  3x +0 = 6

  x = 6/3 = 2

Plot the intercepts and draw the line through them for the graph of this equation.

___

Here, we have suggested graphing strategies that don't involve a lot of manipulation of the equations. The idea is to get there as quickly as possible with a minimum of mistakes.

8 0
3 years ago
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