Will you please either write the question or upload a picture of it so we can help you with it?
Answer:
atq= let no.be x and y
x= 4y-3.......(1)
x-2y=7....(2)
subtracting both eqn
x-x+2y=4y-3-7
2y=4y-10
-2y= -10
y=5 ........second no.
first no...x=7+2y=7+10=17.......first no....
Answer:
(a) 4.98x10⁻⁵
(b) 7.89x10⁻⁶
(c) 1.89x10⁻⁴
(d) 0.5
(e) 2.9x10⁻²
Step-by-step explanation:
The probability (P) to find the particle is given by:
(1)
The solution of the intregral of equation (1) is:
![P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7BL%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2FL%29%7D%7B4%5Cpi%20%2FL%7D%5D%7C_%7Bx_%7B1%7D%7D%5E%7Bx_%7B2%7D%7D%20)
(a) The probability to find the particle between x = 4.95 nm and 5.05 nm is:
![P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7B100%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2F100%29%7D%7B4%5Cpi%20%2F100%7D%5D%7C_%7B4.95%7D%5E%7B5.05%7D%20%3D%204.98%20%5Ccdot%2010%5E%7B-5%7D%20)
(b) The probability to find the particle between x = 1.95 nm and 2.05 nm is:
![P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7B100%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2F100%29%7D%7B4%5Cpi%20%2F100%7D%5D%7C_%7B1.95%7D%5E%7B2.05%7D%20%3D%207.89%20%5Ccdot%2010%5E%7B-6%7D%20)
(c) The probability to find the particle between x = 9.90 nm and 10.00 nm is:
![P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7B100%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2F100%29%7D%7B4%5Cpi%20%2F100%7D%5D%7C_%7B9.90%7D%5E%7B10.00%7D%20%3D%201.89%20%5Ccdot%2010%5E%7B-4%7D%20)
(d) The probability to find the particle in the right half of the box, that is to say, between x = 0 nm and 50 nm is:
![P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7B100%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2F100%29%7D%7B4%5Cpi%20%2F100%7D%5D%7C_%7B0%7D%5E%7B50.00%7D%20%3D%200.5%20)
(e) The probability to find the particle in the central third of the box, that is to say, between x = 0 nm and 100/6 nm is:
![P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7B100%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2F100%29%7D%7B4%5Cpi%20%2F100%7D%5D%7C_%7B0%7D%5E%7B16.7%7D%20%3D%202.9%20%5Ccdot%2010%5E%7B-2%7D%20)
I hope it helps you!
Answer: She makes $58.50 in profit.
Step-by-step explanation:
It costs $2.50 to make each bottle
She sells each bottle for $7
2.50 * 13 = 32.5
It costs her $32.50 to make all the bottles.
7 * 13 = 91
She sells them all for $91.
91 - 32.5 = 58.5
$58.50 is the profit.
Answer: △DEF is congruent to △D'E'F' because you can map △DEF to △D'E'F' using a reflection across the x-axis, which is a rigid motion.
Explanation:
1) Reflections, rotations and translations are rigid transformations, because they do not modify the lengths of the segments nor the angles, so the images and the preimages are congruents.
2) Let's see what transformation map △DEF is to △D'E'F' by analyzing the vertices of preimage and image:
Preimage Image
D (-3, -1) D' (-3, 1)
E (2, -4) E' (2, 4)
F (4, -4) F' (4, 4)
As you see when the image is formed, the coordinate x of the image is kept, and the coordinate y is negated. This rule is (x, y) → (x, - y), which is the rigid transformation reflection across the x-axis.
