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2 years ago

Based on the graph, what is the initial value of the linear relationship? (4 points)

Mathematics

1 answer:

Fittoniya [83]2 years ago

5 0

Answer:

the answer is 5 hope this could help

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In a box there are 6 orange balls, 4 green balls and "x" blue balls. If the probability of removing a blue ball is 1/3, what is

worty [1.4K]

Answer: 2/3 I think

Step-by-step explanation:

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2 years ago

Can you help me do number three?

Alexus [3.1K]

I solved it for you. hopefully this helps

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3 years ago

What is the answer to this equation <img src="https://tex.z-dn.net/?f=10%5Csqrt%7Bx%7D%2020" id="TexFormula1" title="10\sqrt{x}

AveGali [126]

Factor the expression
Use the properties of radicals
Simplify the roots
Calculate
And your solution will be 20 overall 5
Message me if you want me to write it all down!

8 0

3 years ago

Brandon says to get that shade of green, 6 pints of yellow paint need to be added to the bucket. Bianca says that won't work. In

Ksenya-84 [330]

<span>There are 2 pints of blue and 2 pints of yellow in the bucket.
To be 80% yellow, the new color will be (100%-80%=) 20% blue.

2 pints is 20% of (2 pints/0.20=) 10 pints.
With 4 pints in the bucket, to make 10 pints you should add
(10 pints-4 pints=) 6 more pints of yellow paint.

ANSWER: You should add 6 pints of yellow to the 4 pints of green in the bucket to make the new color that is 80% yellow.</span>

3 0

3 years ago

The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82,

ozzi

Answer:

Population variance 579

Population standard deviation 24

Step-by-step explanation:

The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82, 78, 80, 91, 107, 121, 125, 131, and 142.

The population variance is given by:

$\sigma^2=\frac{\sum(x-\mu)^2}{n}$

$\mu=\frac{71+80+82+78+80+91+107+121+125+131+142}{11}$

$\mu=\frac{1108}{11}$

This implies that:

$\sigma^2=\frac{(71-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+(82-\frac{1108}{11})^2+(78-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+...+(142-\frac{1108}{11})^2}{11}$

$\sigma^2=\frac{70006}{121} =579$ to the nearest whole number

The population standard deviation is

$\sigma=\frac{\sqrt{70006} }{11}=24$ to the nearest whole number.

3 0

3 years ago

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