Answer:
8 π or
25.13 unit^3 to the nearest hundredth.
Step-by-step explanation:
(A)
The height of the shell is (2 + x - x^2) and the radius is (2 - x).
V = 2π ∫(2 - x)(x + 2 - x^2) dx between the limits x = 0 and x = 2.
= 2π ∫ (2x + 4 - 2x^2 - x^2 - 2x + x^3) dx
= 2π ∫ (x^3 - 3x^2 + 4 ) dx
= 2π [ x^4/4 - x^3 + 4x ] between x = 0 and x = 2
= 2 π [4 - 8 + 8 )
= 2 π * 4
= 8π
= 25.13 unit^3 to the nearest hundredth.
Answer:
f(-2) = -1
f(0) = -5
f(4) = -1
Step-by-step explanation:
The number inside of f( ) is telling you which equation to use to get the answer.
Example:
f(-2) since -2 is less than 0 you would use (x^2) - 5. So, ((-2)^2) - 5 = 4-5 = -1
f(0) since 0 is less than or equal to 0 you would use (x^2) - 5 again. So, ((0)^2) - 5 = 0-5 = -5
f(4) since 4 is grater than 3 you would use (2^(x-1)) - 9. So, (2^(4-1)) - 9 = -1
<u><em>The Graph, try to make it as straight as possible</em></u>
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Answer:
Step-by-step explanation:
Parameters to describe the movement
Width: W
length: L = 5W
Use the Pyth. Theorem to find the length of the diagonal:
|D| = sqrt(W^2 + [5W]^2) = sqrt(W^2 + 25W^2) = sqrt(26W^2), or
Wsqrt(26) (ans.)