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3 years ago

Find the value of x and y and please show all work.

Mathematics

2 answers:

elena55 [62]3 years ago

6 0

Answer:

x=66

y=48

Step-by-step explanation:

because the two length is same, so the angle x= 66 will be same; y= 180-66-66=48

nata0808 [166]3 years ago

6 0

Step-by-step explanation:

x+y+66=180

66+66=132

180-132=48

66+48+66=180

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Answer:

16 magazines jan sold

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3 years ago

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If a = 4 and 5a(2b – 3a) = 40, what is the value of b?

mamaluj [8]

Answer:

b=7

Step-by-step explanation:

5a(2b – 3a) = 40

Let a=4

5*4(2b-3*4) = 40

20(2b-12) = 40

Divide each side by 20

20/20 (2b-12) = 40/20

2b-12 =2

Add 12 to each side

2b-12+12 = 2+12

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3 years ago

Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A

liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality $\sin ^2\theta +\cos ^2\theta \geq 1$

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

$\sin \theta$ = side opposite to $\theta$ /hypotenuse

$\cos \theta$ = side adjacent to $\theta$ /hypotenuse

$\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta$

$\cos \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta$

So, coordinates of A = $\left ( \cos \theta ,\sin \theta \right )$

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by $x^2+y^2=1$

Put $(x,y)=\left ( \cos \theta ,\sin \theta \right )$

$\cos ^2\theta +\sin ^2\theta =1$

So, $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ satisfies the equation $x^2+y^2=1$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ inside the circle, $\cos ^2\theta +\sin ^2\theta$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ outside the circle, $\cos ^2\theta +\sin ^2\theta >1$

So, only points on the circle satisfy the given inequality.

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2 years ago

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Yanka [14]

Answer:

13.99 min

Step-by-step explanation:

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3 years ago

What is the solution of the system? Use elimination. 7x + 5y = 19 −7x − 2y = −16

netineya [11]

Make the coefficient of y the same in both equations:

To do this, multiply equation one by 2, and equation two by 5 (this will make the coefficient 10 in both).

14x + 10y = 38
-35x - 10y = -80

Eliminate the y variable by adding the equations from each other

(14x + 10y = 38)
+ (-35x - 10y = -80)
= -21x + 0y = -42

We now have -21x = -42. The y variable has been eliminated.

Solve for x

-21x = -42

Divide both sides by -21 to get x on its own.

x = 2

Substitute x into the equation to find y.

7*2+5y=19

14+5y=19

Subtract 14 from both sides.

5y=19-14

5y=5

Divide by 5 on both sides to get y on its own.

y=5/5

y=1

The answer is (2,1)

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3 years ago