How do you solve 6 7/8 + 1 2/8 =

1 answer:

8 0

$6\frac{7}{8}+1\frac{2}{8}=(6+\frac{7}{8})+(1+\frac{2}{8})=(6+1)+\left(\frac{7}{8}+\frac{2}{8}\right)\\\\=7+\frac{7+2}{8}=7+\frac{9}{8}=7+\frac{8+1}{8}=7+\frac{8}{8}+\frac{1}{8}=7+1+\frac{1}{8}\\\center{\boxed{\boxed{=8\frac{1}{8}}}$

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Answer:

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A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the ba

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Option C: 0.8889 is the probability of choosing an orange marble and a green marble.

<h2>Given that:</h2>

Number of red marbles is 5

Number of orange marbles is 2

Number of yellow marbles is 1.

Number of green marbles is 2.

<h2>Explanation and Calculations:</h2>

So there are in total 10 marbles.

Two marbles can be chosen in $^{10}C_2$ ways = 90/8

Now the favorable event is when one green marble and one orange marble is chosen. The number of ways this can be done is $^{2}C_1 \times ^{2}C_1 = 4$