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Reil [10]
3 years ago
6

If n is a positive integer and the product all the integeres from 1 to n inclusive is a multiple of 990 what is the least possib

le value of n
Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0
Hello,

Since 990=2*3²*5*11 ==>n=11
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after 4 mins the sub reaches 27 feet
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3 years ago
Please help!
crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

4 0
2 years ago
Solve the simultaneous equations 8 x + 5 y = 28 4 x + 5 y = 16
Nostrana [21]

Answer:

x=3, y=0.8

Step-by-step explanation:

8x+5y=28

4x+5y=16

Subtract the second simultaneous equation from the first.

You are left with: 4x=12

12/4=3

x=3

Substitute this back into one of the equations.

8(3)+5y=28

8*3=24

28-24=4

4=5y

4/5=0.8

y=0.8

5 0
3 years ago
Read 2 more answers
Given h(x) = 5x -1, find h(1).
Norma-Jean [14]
H(1) = 4


h(1)= 5 x 1 -1
=5-1
=4
hope that helps <3
5 0
3 years ago
Find the value of X and Y.
Elis [28]

Answer:x=63.4° y= 8.16

Step-by-step explanation:

5 0
3 years ago
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