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2 years ago

Lines c and d are perpendicular and if the slope of line c is -4 what is the slope of line d ?

2 answers:

8 0

Perpendicular lines, slope is opposite and reciprocal. so if the slope of line c is -4 then the slope of line d will be 1/4

Hope it helps

siniylev [52]2 years ago

4 0

The answer to your question is 1/4

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(4200 + 75) + 5 = ( ? )+ (75+5)<br> What would make it true?

geniusboy [140]

Answer:

4200

Step-by-step explanation:

4280=(?)+80

So the answer is 4200

8 0

2 years ago

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0.5 is ten times as great as?

GarryVolchara [31]

Let's cut the chit chat, and formalities. I'm not one for greetings or unnecessary niceties.

Divide 0.5 by 10=
0.05

Check work.
0.05 x 10 = 0.5

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3 years ago

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8x2 - 6x + 3 – 2x – 10x?

Marina CMI [18]

Answer:

8 $x^{2}$ + 3 + -6x

Step-by-step explanation:

First we need to find the like terms so that we could add them. In this case the like terms are,

1. 6x , -2x , -10x

So, these are the only terms that we can add in this expression.

Hence,

=> 8 $x^{2}$ + 3 + (6x - 2x - 10x)

=> 8 $x^{2}$ + 3 + -6x

And this is as simple as this expression can go until we find the value of "x" which is not yet told.

Hope my answer helped.

4 0

2 years ago

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A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago

When three professors are seated in a restaurant, the hostess asks them: "Does everyone want coffee?" The first professor says:

dalvyx [7]

the first two professors did not know if everyone wanted coffee because the third professor had to choose yes or no if he wanted coffee. the first two professors were waiting for the third to say something, and when he said no, they knew he did not want coffee. if one of the first two professors said no, the answer would be no.

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2 years ago