All categories

3 years ago

A store has a outfit that is $35.00 and 50% of what is the price now.

Mathematics

2 answers:

natta225 [31]3 years ago

7 0

Answer:

Step-by-step explanation:

The price is x

50% of the price is $35

x*0.5 = 35
x = 35/0.5
x = 70

Answer is $70

Semenov [28]3 years ago

5 0

Answer:

Step-by-step explanation:

50% off the price of $35

= $35 ( 0.50)

= $17.50 (price now)

You might be interested in

M is the midpoint of AB with a line over it. <br><br> A(5, 6) and B(13, 4). Find M.

irina1246 [14]

Answer:

M(9;5), I think so. M is midpoint of AB so separate 2

8 0

2 years ago

jerry climbed 210 feet in elevation. He then went down 300 feet. What integer represents his total change in elevation

Gala2k [10]

Answer:

210-300=-90

Step-by-step explanation:hope this helps plz mrk me brainliest

3 0

2 years ago

Plz help. Simplifying simplify the answers

galben [10]

9/32
1/3
1/9
7/18
7/20
5/44
Still in fractions?

6 0

2 years ago

Read 2 more answers

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

2 years ago

Write a rule for the linear function in the graph.

labwork [276]

3=4m+ b
-1=3m+b

m=4
plug in to either equation,
3=16+ b
b=-13

Thus, C would be the answer.

6 0

3 years ago

Read 2 more answers