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3 years ago

I’m doing a test and it’s already hard

Mathematics

2 answers:

Goryan [66]3 years ago

8 0

Answer:

I mean, the best thing to do is to guess the best guess. I'm not really the type that knows everything, though.

Allushta [10]3 years ago

6 0

Answer:

I mean, the best thing to do is to guess the best guess. I'm not really the type that knows everything, though.

Step-by-step explanation:

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The owner of the pizza chain wants to monitor the total weight of pepperoni. Suppose that for pizzas in this population, the wei

Whitepunk [10]

Answer:

The probability that the mean weight of the pepperoni from the sample of 64 pizzas is greater than 251 g is 0.02275.

Step-by-step explanation:

We are given that the owner of the pizza chain wants to monitor the total weight of pepperoni. Suppose that for pizzas in this population, the weights have a mean of 250 g and a standard deviation of 4 g.

Management takes a random sample of 64 of these pizzas.

Let $\bar X$ = sample mean weight of the pepperoni.

The z score probability distribution for sample mean is given by;

Z = $\frac{X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 250 g

$\sigma$ = standard deviation = 4 g

n = sample of pizzas = 64

Now, the probability that the mean weight of the pepperoni from the sample of 64 pizzas is greater than 251 g is given by = P( $\bar X$ > 251 g)

P( $\bar X$ > 251 g) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{251-250}{\frac{4}{\sqrt{64} } }$ ) = P(Z > 2) = 1 - P(Z $\leq$ 2)

= 1 - 0.97725 = 0.02275

The above probabilities is calculated by looking at the value of x = 2 in the z table which has an area of 0.97725.

Hence, the probability that the mean weight of the pepperoni from the sample of 64 pizzas is greater than 251 g is 0.02275.

4 0

4 years ago

In right triangle abc shown below, altitude cd is drawn to hypotenuse (ab). explain why δabc ∼ δacd.

Komok [63]

First prove that ∆CBD ~ ∆ABC.
Each triangle has a right triangle and each includes angle B. The triangles are similar.
You can use similar reasoning to show that ∆ACD ~ ∆ABC.
To show that ∆CBD ~ ∆ACD, begin by showing that angleACD = angle B because they are both complementary to angleDCB. Then you can use Similarity Postulates.
I found the image of the triangle that was missing the question! Attached triangle.

4 0

3 years ago

Instructions: use the ratio of a 45-45-90 triangle to solve for the variables. Leave your answers as radicals in simplest form

DIA [1.3K]

Answer:

v=14, u=14

Step-by-step explanation:

The 45-45-90 theorem states that the hypotenuse is $\sqrt{2}$ times the bases of the triangle. So, to find one of the bases, we need to divide $\sqrt{2}$ . Thus, $\frac{12\sqrt{2} }{\sqrt{2} } = 12$ .

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3 years ago

Identify two factors that have an estimated product of 2000

tankabanditka [31]

The dog eats seral all day

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4 years ago

Please answer this question with explanation

makvit [3.9K]

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