All categories

3 years ago

How do i graph -5,3 on a graph

Mathematics

2 answers:

serious [3.7K]3 years ago

5 0

Answer:

you would go backwards 5 on the x axis and go 3 upwards on the y axis above the -5

Step-by-step explanation:

ikadub [295]3 years ago

3 0

Step-by-step explanation:

I am assuming (-5,3) is a coordinate point.

To plot this, you need a graph.

On the graph, you must go left 5 points on the x-axis from the origin

Then go up 3 points on the y-axis

That place is the coordinates (-5.3)

You might be interested in

Two classes are having pizza parties. Ms. Rodriguez’s class decides to order enough so that every 3 students will have 2 pizzas.

SVEN [57.7K]

Answer:

Pizzas will be ordered by the two classes

7 0

3 years ago

Using the least number of coins how many quarters, dimes, nickels, and pennies to make $1.74

SpyIntel [72]

Let's use our largest amount (quarter) to see how many can fit evenly into 1.74.

1.74/0.25 = 6.96
The most quarters that can fit into $1.74 is 6.

---Multiply $0.25 by 6 = $1.50

---Subtract $1.50 from $1.74 = $0.24

---We need to use the rest of the coins to fill up $0.24.

Now let's use our second largest amount (dime) to see how many can fit evenly into 0.24.

0.24/0.10 = 2.4
The most dimes that can fit into $0.24 is 2.

---Multiply $0.10 by 2 = $0.20

---Subtract $0.20 from $0.24 = $0.04

No nickels can fit into $0.04, because they are worth $0.05.

We can use our least amount (pennies) to fill in the $0.04 remaining.

Your answer is 6 quarters, 2 dimes, and 4 pennies.

4 0

3 years ago

Select the correct answer.<br> Simplify the following expression.

OlgaM077 [116]

Answer:

A. 1/49, or 0.02040

3 0

2 years ago

How do you know where to put the constant when finding general solutions for differential equations?

Norma-Jean [14]

Let's suppose we want to solve $y'=y$ with $y(0)=2$ . Separating variables and integrating, we get

$\displaystyle\int\dfrac{\mathrm dy}y=\int\mathrm dx\implies\ln|y|=x+C\implies y=e^{x+C}$

Leaving the solution in this form, the initial condition gives

$2=e^{0+C}=e^C\implies C=\ln2$

This means the solution is $y=e^{x+\ln2}$ .

Now if we were to write $y=e^{x+C}=e^xe^C=Ce^x$ , then we would have found

$2=Ce^0\implies C=2$

so that the solution would have been $y=2e^x$ .

But these two solutions are the same, since $y=e^{x+\ln2}=e^xe^{\ln2}=2e^x$ . So we get the same solution regardless of where we place $C$ , despite getting different values for $C$ .

5 0

3 years ago

You spin the spinner twice and record the sum of the numbers you get.

Snowcat [4.5K]

Answer:i think its A.

Step-by-step explanation:*you only spin twice, the only explination would be if on the first spin u got 3 or two and on the second spin you go 3 or 2, either way lets say spin 1 landed on #2 spin 2 landed on #3 which equals 5

5 0

4 years ago