List at least 4 types of works covered by copyright law

What is tnylnk? I keep seeing people leave answers with this.....can someone explain what this is, please...I might give brainie

Naddika [18.5K]

Answer:

ITS A SCAM IT DOWN LOADS NASTY STUFF ON TO UR COMPUTER

Explanation:

hope this helps

8 0

2 years ago

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In a C++ program, one and two are double variables and input values are 10.5 and 30.6. After the statement cin >> one >

SSSSS [86.1K]

Answer:

variable one stores 10.5 and two stores 30.6

Explanation:

In c++ language, the cout keyword is used to write to the standard output. The input from the user is taken by using the cin keyword.

For the input from the user, a variable need is declared first.

datatype variable_name;

The input can be taken one at a time as shown.

cin >> variable_name;

The input for more than one variable can be taken in a single line as given by the syntax below.

1. First, two variables are declared.

datatype variable_name1, variable_name2;

2. Both input is taken simultaneously as shown.

cin >> variable_name1, variable_name2;

For the given scenario, two double variables are declared as below.

double one, two;

The question mentions input values for the two double variables as 10.5 and 30.6.

3. The given scenario takes both the values as input at the same time, in a single line as shown below.

cin >> one >> two;

4. After this statement, both the values entered by the user are accepted.

The values should be separated by space.

First value is stored in the variable one.

Second value is stored in the variable two.

5. The user enters the values as follows.

10.5 30.6

6. The value 10.5 is stored in variable one.

7. The value 30.6 is stored in variable two.

The c++ program to implement the above is given below.

#include <iostream>

using namespace std;

int main() {

double one, two;

cout << " Enter two decimal values " << endl;

cin >> one >> two;

cout << " The input values are " << endl;

cout << " one : " << one << " \t " << " two : " << two << endl;

return 0;

}

OUTPUT

Enter two decimal values

10.5 30.6

The input values are

one : 10 two : 530.6

6 0

2 years ago

The code size of 2-address instruction is________________.? 5 bytes? 7 bytes? 3 bytes? 2 bytes

Finger [1]

Answer:

7 bytes

Explanation:

2 Address Instruction

The 2 address instruction consist 3 components in the format.

One is opcode,other two are addresses of destination and source.

Example-

load b,c | Opcode destination address,source address

add a,d | Opcode destination address,source address

sub c,f | Opcode destination address,source address

Opcode consists of 1 bytes whereas destination address and source address consist of 3 bytes each.

(1+3+3) bytes=7 bytes

5 0

2 years ago

Please tell fast plzzzzzz.

shepuryov [24]

Answer:

true....................

6 0

2 years ago

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Write a program that reads an integer and determines and prints whether it's odd or even. [Hint: Use the remainder operator (%).

Sloan [31]

<h2>Explanation:</h2>

The source code, written in Java, and a sample output have been attached to this response. It contains comments explaining certain parts of the code.

A few things to note are;

(i) The Scanner class is imported to allow user's interact with the program. This is done by writing the import statement at the top of the code as follows;

import java.util.Scanner;

(ii) An object of the Scanner class is created to receive inputs from the user. The object is called input and created as follows;

Scanner input = new Scanner(System.in);

(iii) Since the user is expected to enter an integer, the nextInt() method of the Scanner object is used to receive the integer and this is saved in a variable called number. i.e

int number = input.nextInt();

(iv) A number x, is even if its remainder when divided by 2 is 0. i.e

if x % 2 = 0, then x is even. Otherwise it is odd.

The user's input received and saved in a variable called number is then checked using if and else blocks to check if it is even or not and can be written as follows;

if(number % 2 == 0){

System.out.println(number + " is even");

}else {

System.out.println(number + " is odd");

}

4 0

3 years ago