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3 years ago

What is the relationship between the 6s in the number 7,664

Mathematics

1 answer:

olga55 [171]3 years ago

8 0

The relationship between the 6's in 7,664 is that it can be 600 and 60.

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Lol I wasnt paying attention pleaseeee help

mr_godi [17]

Answer:

3 1/3

Step-by-step explanation:

super easy, just multiply them

5/1*1/3 and you get 10/3 and you simplify and get 3 1/3 pizza

5 0

3 years ago

Read 2 more answers

(2x - y=2 (2x - 2y=4

Olegator [25]

2x-y=2--------------(i)

2x-2y=4------------(ii)

Multiplying eqn i by 2 and subtracting with ii

4x-2y=4

2x-2y=4

- + -

________

2x=0

X=0

Putting the value of x in i

2×0-y=2

-y=2

y=-2

Hence the value of x is 0 and y is -2

4 0

3 years ago

Read 2 more answers

An acre measures 4840 square yards. In a city, a lot on which a single-

belka [17]

The lot is 9.2% of the an acre.

Given:

Area of an acre = 4840 sq. yards

Area of lot = 40 by 100 ft = $40 ]\times 100 = 4,000 $ ft^{2}$

Convert the area of the lot to feet ( $9 ft^{2} = yd^{2}$ ):

Therefore:

Area of lot = $\frac{4,000}{9} = 444.4 $ yd^{2}$

Percentage occupied by the lot = area of lot / area of acre x 100

$= \frac{444.4}{4840} \times 100\\\= 9.2$

The lot therefore is 9.2% of the an acre.

Learn more here:

brainly.com/question/20730855

7 0

3 years ago

If a square has an area of 100 ft squared, what is the measure of each side? Explain? HELPP

Gekata [30.6K]

Answer

10 ft sides

Step-by-step explanation:

Since its squared the easiest way to figure out the sides is to square root the area and square root of 100 is 10

5 0

3 years ago

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Find the area in cm2 of a rhombus whose side length is 29 cm and

kotegsom [21]

$\left(\frac{d}{2}\right)^2+\left(\frac{d+2}{2}\right)^2=29^2\\\\\frac{d^2}{4}+\frac{d^2+4d+4}{4}=841\ \ \ \ /\cdot4\\\\d^2+d^2+4d+4=3364\\\\2d^2+4d+4-3364=0\\\\2d^2+4d-3360=0\ \ \ \ /:2\\\\d^2+2d-1680=0$

$a=1;\ b=2;\ c=-1680\\\\\Delta=b^2-4ac\to\Delta=2^2-4\cdot1\cdot(-1680)=4+6720=6724\\\\\sqrt\Delta=\sqrt{6724}=82\\\\d_1=\frac{-b-\sqrt\Delta}{2a}\to d_1=\frac{-2-82}{2\cdot1} < 0\\\\d_2=\frac{-b+\sqrt\Delta}{2a}\to d_2=\frac{-2+82}{2\cdot1}=\frac{80}{2}=40\ (cm)\\\\d=40cm;\ d+2=42cm\\\\A_r=\frac{d(d+2)}{2}\to A_r=\frac{40\cdot42}{2}=840\ (cm^2)$

3 0

4 years ago