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ohaa [14]
3 years ago
5

What is 1/2 - 3/10 write it in simplist form

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0

Answer:

1/5

Step-by-step explanation:

There is an easy way I learned.

You can multiply 1/2 by 5/5

so you get 5/10 - 3/10

and the you subtract 5-3=2

2/10

simplify 1/5

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Answer:

That would be an isosceles triangle.

Step-by-step explanation:

Isosceles triangles have two sides the same length and one side a different length. I hope this helps! :)

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a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

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3 years ago
Solve the equation by completing the square.
Varvara68 [4.7K]

Answer:

<u>A</u>

Step-by-step explanation:

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Option A

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