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Alja [10]
3 years ago
5

How many cells does the organism have?\

Computers and Technology
2 answers:
Masja [62]3 years ago
7 0

Answer:

approx. 27.2 trillion cells in our body

Explanation:

avanturin [10]3 years ago
4 0

Answer:

See it depends upon the organism like human,animal,microbes,etc.amswer is below.

Explanation:

Humans have 37.2 Trillion cells

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Class of software called "malware"

Explanation:

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In this question, we give two implementations for the function: def intersection_list(lst1, lst2) This function is given two lis
castortr0y [4]

Answer:

see explaination

Explanation:

a)Worst Case-time complexity=O(n)

def intersection_list(lst1, lst2):

lst3 = [value for value in lst1 if value in lst2]

return lst3

lst1 = []

lst2 = []

n1 = int(input("Enter number of elements for list1 : "))

for i in range(0, n1):

ele = int(input())

lst1.append(ele) # adding the element

n2 = int(input("Enter number of elements for list2 : "))

for i in range(0, n2):

ele = int(input())

lst2.append(ele) # adding the element

print(intersection_list(lst1, lst2))

b)Average case-time complexity=O(min(len(lst1), len(lst2))

def intersection_list(lst1, lst2):

return list(set(lst1) & set(lst2))

lst1 = []

lst2 = []

n1 = int(input("Enter number of elements for list1 : "))

for i in range(0, n1):

ele = int(input())

lst1.append(ele)

n2 = int(input("Enter number of elements for list2 : "))

for i in range(0, n2):

ele = int(input())

lst2.append(ele)

print(intersection_list(lst1, lst2))

6 0
3 years ago
Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards
konstantin123 [22]

Answer:

for(i = 0 ; i < NUM_VALS; ++i)

{

   cout << courseGrades[i] << " ";

}

cout << endl;

for(i = NUM_VALS-1 ; i >=0 ; --i)

{

   cout << courseGrades[i] << " ";

}

cout << endl;

Explanation:

The first loop initializes i with 0, because we have to print the elements in order in which the appear in the array. We print each element, adding a space (" ") character at its end. After the loop ends, we add a new line using endl.

The second loop will print the values in a reverse order, so we initialize it from NUM_VALS-1, (since NUM_VALS = 4, and array indices are 0,1,2,3). We execute the loop till i >= 0, and we print the space character and new line in a similar way we executed in loop1.

4 0
3 years ago
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