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3 years ago

Calculate the object's velocity as shown on the position-time graph,

Physics

1 answer:

Cloud [144]3 years ago

4 0

Answer:

10 m/s

Explanation:

The following data were obtained from the question:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Velocity (v) =.?

Next, we shall determine the change in displacement of the object and likewise the change in time.

This can be obtained as follow:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Change in displacement (Δd) = d2 – d1

Change in displacement (Δd) = 60 – 10

Change in displacement (Δd) = 50 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Change in time (Δt) = t2 – t1

Change in time (Δt) = 5 – 0

Change in time (Δt) = 5 s

Finally, we shall shall calculate the velocity of the object as illustrated below:

Change in displacement (Δd) = 50 m

Change in time (Δt) = 5 s

Velocity (v) =.?

v = Δd/Δt

v = 50/5

v = 10 m/s

Therefore, the velocity of the object is 10 m/s.

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3 years ago

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An electric generator contains a coil of 130 turns of wire, each forming a rectangular loop 74.6 cm by 24.9 cm. The coil is plac

Gelneren [198K]

Answer:

10.85 kV

Explanation:

The maximum value of the emf (ε) produced can be calculated using Faraday's law equation:

$\epsilon = - \frac{N*d(\phi)}{dt} = - \frac{N*d(BAcos(\theta))}{dt}$ (1)

<u>Where:</u>

N: is the turns of wire = 130 turns

Φ: is the magnetic flux = BAcos(θ)

B: is the magnetic field = 3.82 T

A: is the area of the coil = a*b = 0.746 m*0.249 m = 0.186 m²

θ: is the angle between the magnetic field lines and the normal to A = ωt = 2πft

f: is the frequency = 1120 rev/min = 18.7 rev/s

From equation (1) we have:

$\epsilon_{max} = NBA2\pi f sin(2\pi ft) = NAB2\pi f = 130*0.186 m^{2}*3.82 T*2*\pi*18.7 rev/s = 10852.8 V = 10.85 kV$

Therefore, the maximum value of the emf produced is 10.85 kV.

I hope it helps you!

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4 years ago

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How is the position vs. time graph with the cart moving towards the sensor with decreasing speed different than the position vs.

IrinaVladis [17]

Answer:

if Y is the position and X the time: in the first one you will see a crescent function that starts sharp and starts to curve down as the time pases. as the cart is slowing down, you will need more time to move the same as before.

Y (position)

sensor-------------------------------------------------------------------

I o

I------------------------------------------------------------------------------------- X (time)

in the second case the cart starts close to the sensor and starts getting sharper and sharper as the time pases. This is because the velocity is increasing, so for each second that pases, you will travel more distance that the second before it.

Y (position)

sensor ----------------------

I o

I------------------------------------------------------------------------------------- X (time)

i hope you can understand it, kinda hard to do graphs here.

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4 years ago

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I hope this helped!

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3 years ago

The velocity of sound in air at STP (Standard Temperature and Pressure) is approximately 344 m/s. If the frequency of the sound

exis [7]

Answer:

0.066m

Explanation:

use the formula

velocity= frequency × wave length

344m/s = 5200Hz× wavelength

wavelength = 344m/s/5200Hz

wavelength = 0.066m(to 2 sig fig)

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3 years ago