Because many objects in space don't radiate any optical (visible) radiation at all.
And other objects, like stars, radiate a lot of invisible radiation in addition to the
visible light from them. So the ability to detect and measure invisible radiation
makes it possible to learn a lot more about objects in space than we could if
we could only use their visible light.
Answer:
a) 0 < r < R: E = 0, R < r < 2R: E = KQ/r^2, r > 2R: E = 2KQ/r^2
b) See the picture
Explanation:
We can use Gauss's law to find the electric field in all the regions:
EA = qen/e0 where qen is the enclosed charge
Remember that the electric field everywhere outside a sphere is:
E(r) = q/(4*pi*eo*r^2) = Kq/r^2
a)
- For 0 < r < R: There is not enclosed charge because all of it remains on the outer layer of the conducting sphere, therefore E = 0 EA = 0/e0 = 0 E = 0
- For R < r < 2R: Here the enclosed charge is equal Q E = Q/(4*pi*eo*r^2) = KQ/r^2
- For r > 2R: Here the enclosed charge is equal 2Q E = Q/(4*pi*eo*r^2) + Q/(4*pi*eo*r^2) = 2Q/(4*pi*eo*r^2) = 2KQ/r^2
b) At the beginning there is no electric field this is why you see a line in zero, In R the electric field is maximum and then it starts to decrease exponentially with the distance and finally in 2R the field increase a little due to the second sphere to then continue decreasing exponentially with the distance
To solve this problem we will start by differentiating the values in each of the states of matter. Subsequently through the thermodynamic tables we will look for the values related to the entropy, enthalpy and respective specific volumes. Through the relationship of Power defined as the product between mass and enthalpy and mass, specific volume and pressure, we will find the energetic values in the two states investigated. We will start defining the states
State 1
From steam table
Now
<em>As 1-2 is isentropic</em>
State 2
From steam table
PART A) The power produced by turbine is the product between the mass and the enthalpy difference, then
b) Pump Work
State 3
The Work done by the pump is
Answer:
The orbital diagram represents the filling of electrons in the sub levels of an orbit. The filling of the orbitals in sub- levels follow some basic rules and principles.
The orbital diagram of an orbit containing 16 electrons will be as follows:
1s²2s²2p⁶3s²3p⁴
- The maximum number of electrons in each sublevel of the orbitals are:
- 2 electrons for s-sublevel with one orbital
- 6 electrons for p-sublevel with three orbital
- 10 electrons for d-sublevel with five orbital
- 14 electrons for f-sublevel with seven orbital
Answer:
The correct answer would be downwards
Hope this helps have a good day