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2 years ago

The system of equations shown below is graphed on a coordinate grid:

Mathematics

2 answers:

konstantin123 [22]2 years ago

8 0

Your answer would be the first option, (-2, 2).

We can solve this system of equations by adding them together, as the +x and -x will cancel:

3y + x = 4

+2y - x = 6

5y = 10

y = 2

Now we can find the x value by substituting the y value into one of the equations:

3(2) + x = 4

6 + x = 4

x = -2

Therefore your answer is (-2, 2). We know that it is the first option and not the last option because the point (-2, 2) does lie on both lines as it satisfies both equations when substituted in.

I hope this helps!

ankoles [38]2 years ago

5 0

Answer:

A) (-2,2) lies on both lines

Step-by-step explanation:

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GenaCL600 [577]

Answer:

$(A)\ a=-6;b=4\\\\ (B)\ a=6;b=-4$

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

$y=mx+c$

Where "m" is the slope and "c" is the y-intercept.

By definition:

1. If the lines of the System of equations are parallel (whrn they have the same slope), the system has No solutions.

2. If the they are the same exact line, the System of equations has Infinite solutions.

(A) Let's solve for "y" from the first equation:

$3x-2y=-1\\\\-2y=-3x-1\\\\y=\frac{3}{2}x+\frac{1}{2}$

You can notice that:

$m=\frac{3}{2}\\\\c=\frac{1}{2}$

In order make that the System has No solutions, the slopes must be the same, but the y-intercept must not. Then, the values of "a" and "b" can be:

$a=-6\\\\b=4$

Substituting those values into the second equation and solving for "y", you get:

$-6x+4y=-2\\\\4y=6x-2\\\\y=\frac{6}{4}x-{2}{4}\\\\y=\frac{3}{2}x-\frac{1}{2}$

You can idenfity that:

$m=\frac{3}{2}\\\\c=-\frac{1}{2}$

Therefore, they are parallel.

(B) In order make that the System has Infinite solutions, the slopes and the y-intercepts of both equations must be the same. Then, the values of "a" and "b" can be:

$a=6\\\\b=-4$

If you substitute those values into the second equation and then you solve for "y", you get:

$6x+(-4y)=-2\\\\-4y=-6x-2\\\\y=\frac{-6}{-4}x-\frac{2}{-4}\\\\y=\frac{3}{2}x+\frac{1}{2}$

You can identify that:

$m=\frac{3}{2}\\\\b=\frac{1}{2}$

Therefore, they are the same line.

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