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Ludmilka [50]
3 years ago
7

Pls help I’ll mark u brain

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

A

Step-by-step explanation:

It would be A,

As we can see, p*c =60 for every value in the chart. We can rearrage this to get c=60/p

<em>I hope this helped! :)</em>

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f(x) = −16x2 + 24x + 16 Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points) Part B: Is the vertex
DerKrebs [107]

Answer:

see below

Step-by-step explanation:

f(x) = −16x^2 + 24x + 16

Set equal to zero to find the x intercepts

0  = −16x^2 + 24x + 16

Factor out -8

0 = -8(2x^2 -3x-2)

Factor

0 = -8(2x +1) (x-2)

Using the zero product property

2x+1 =0    x-2 =0

x = -1/2      x=2

The x intercepts are -1/2   ,2

Since the coefficient of x^2 is negative the graph will open down and the vertex will be a maximum

The x value of the maximum is 1/2 way between the zeros

(-1/2+2) /2 = 1.5/2 =.75

To find the y value substitute into the function

f(.75) = -8(2x +1) (x-2)

        =-8(2*.75+1) (.75-2)

        = -8(2.5)(-1.25)

         =25

The vertex is at (.75, 25)

We have the zeros, and  the vertex.  We know the graph is symmetrical about the vertex

3 0
3 years ago
What is the distance between A(-8, 4) and B(4, -1)?
Anettt [7]

Answer:

The distance between A(-8, 4) and B(4, -1) is 13 units.

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula given by:

\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (<em>x₁, y₁</em>) and let B(4, -1) be (<em>x₂, y₂</em>). Substitute:

d=\sqrt{(4-(-8))^2+(-1-4)^2}

Evaluate:

d=\sqrt{(12)^2+(-5)^2}

So:

d=\sqrt{144+25}=\sqrt{169}=13\text{ units}

The distance between A(-8, 4) and B(4, -1) is 13 units.

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Answer:

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Step-by-step explanation:

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