The correct question is
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?
we have that
y=2x
y=x</span>²+2
y=2x²
using a graph tool
see the attached figure
<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)
The range of the graph y=2x is the interval (-∞,∞)
The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)
therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>
Answer:
Step-by-step explanation:
Let (2n-1) and (2n+1) be the consecutive, odd numbers.
(2n-1)(2n+1) = 143
4n² - 1 = 143
4n² = 144
n² = 36
n = 6
2n-1 = 11
2n+1 = 13
The numbers are 11 and 13.
Answer:
See explanation
Step-by-step explanation:
The range of the cosine function is 
Therefore
is not defined.
Assuming your question is rather 
Then
in the second quadrant.


He traveled 48 feet more or you could say he traveled 16 yards more