Answer:
205 litres
Step-by-step explanation:
The expression that gives the volume of water in Eduardo's pool (in liters) is:
where m is time, in minutes
After 
minutes (
minutes), the volume is will be:
= 205 litres
The volume of water in the poll will be 205 litres.
Answer:
a. The probability is not equal to 1
b. P (A') = 0.70
c. P ( A U B ) = 0.80
d. P ( A' ∩ B' ) = 0.20
Step-by-step explanation:
a. Because these A and B are disjoint
b. since the probability of A is 0.30 then the probability of A compliment is
P(A compliment ) = 1 - P (A)
P(A compliment ) = 1-0.30
P(A compliment ) = 0.70
c. Since event are disjoint then intersection of A and B is 0, so probability of A U B is;
P ( A U B ) = P (A) + P(B) - P(A∩ B)
P ( A U B ) = 0.30 + 0.50 - 0
P ( A U B ) = 0.80
d. The inetrsection of compilments of A and B are:
by using De Morgan's Law we have,
P ( A' ∩ B' ) = P [(A U B )']
P ( A' ∩ B' ) = 1 - P ( A U B )
P ( A' ∩ B' ) = 1 - 0.80
P ( A' ∩ B' ) = 0.20
Answer:
a) The level of significance is large because here z is not appropriate.
b) The true critical value is larger than z because the level of significance is large.
Step-by-step explanation:
a) Based on the question under consideration, the true level of significance is larger than .05 level of significance is large, the reason being that z is not appropriate in this case.
b) The true critical value is larger than that of the critical z, this is because the level of significance is large.
t* in P(T > t*) = 0.975 is more than z* = 1.96 in P(z> z*) =0.975
Answer:
The answer is D ⇒ -4log(-x + 4)
Step-by-step explanation:
From the graph we chose the point of x-intercept (3 , 0)
∵ f(x) = -4log(-x + 4)
∴f(3) = -4log(-3 + 4) = -4log(1)
∵ log(1) = 0
∴f(3) = 0
If x = 0
∴ f(0) = -4log(0 + 4) = -4log4 = -2.40 ⇒ same value on the graph
∴ The answer is (D)
Given:
The triangles DEF is similar to GHF.
The objective is to find a similar ratio of DF/DE.
Explanation:
Using the basic proportionality theorem, for the similar triangles DEF and GHF,
Considering the first two ratios of equation (1),
On interchanging the segments further,
Hence, the required segment in the blanks is GF/GH.
