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2 years ago

Are You guys up for math?? Its 6th grade math though!! so are you ready?? l want help please.

Mathematics

1 answer:

katen-ka-za [31]2 years ago

3 0

The ratio would be 4:1.

Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 64 and 16 is 16

Divide both terms by the GCF, 16:

64 ÷ 16 = 4

16 ÷ 16 = 1

The ratio 64 : 16 can be reduced to lowest terms by dividing both terms by the GCF = 16 :

64 : 16 = 4 : 1

Therefore:

64 : 16 = 4 : 1

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THE GREATEST PRODUCT

Alex17521 [72]

Answer:

7*6543=45801

Step-by-step explanation:

We have the digits 34567 and must arrange them into a product with the largest possible value.

It's clear that we must place the largest digits to the left, so they represent larger numbers to multiply.

Let's try with:

7654*3=22962

765*43=32895

76*543=41268

7*6543=45801

This last combination definitely produces the largest product

Answer: 7*6543=45801

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2 years ago

12.15x19 Need this asap thanks yall have a blessed day :)

valentinak56 [21]

Answer:

The answer would be 230.85

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2 years ago

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4= -2(x-2) +4 please help I’ll give you points!

Elina [12.6K]

<h3>Solution:</h3>

4 = -2(x-2) + 4

or, 4 = -2x + 4 + 4

or, 4 = -2x + 8

or, 4 - 8 = -2x

or, -4 = -2x

or, -4/-2 = x

or, 2 = x

<h2>Answer:</h2>

The value of x is 2.

4 0

2 years ago

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Someone please explain how to do this problem? :) Factor completely 2c5 + 44c4 + 242c3.

frez [133]

2c5+44c4+242c32c5+44c4+242c3=2c3(c+11)(c+11)

8 0

3 years ago

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In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle. Find the measure

soldi70 [24.7K]

Given:

In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.

To find:

The measures of the 2 acute angles of the triangle.

Solution:

Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,

$x+(2x+12)+90=180$

$3x+102=180$

$3x=180-102$

$3x=78$

Divide both sides by 3.

$x=\dfrac{78}{3}$

$x=26$

The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:

$2x+12=2(26)+12$

$2x+12=52+12$

$2x+12=64$

Therefore, the measures of two acute angles are 26° and 64° respectively.

8 0

2 years ago