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Maksim231197 [3]
4 years ago
14

the altitude of the hypotenuse of a right triangle divides the hypotenuse into segments of lengths 14 and 8. what is the length

of the altitude.

Mathematics
1 answer:
lisov135 [29]4 years ago
3 0

Answer:

B. 4\sqrt{7}

Step-by-step explanation:

The right triangle altitude theorem states that the altitude of a right angled triangles formed on the hypotenuse is equal to the geometric mean of the 2 line segments it creates.

This can be represented as:

h = \sqrt{(xy)}

Where,

h = the length of the altitude,

x and y are the lengths of the 2 segments formed.

Therefore, the length of the altitude = h = \sqrt{(14*8)}

h = \sqrt{112}

h = \sqrt{16}*\sqrt{7}

h = 4\sqrt{7}

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$2,462,825.99 is the interest accrued

Step-by-step explanation:

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8 0
3 years ago
Fiona divided 3x2 + 5x – 3 by 3x +2. The expression represents the remainder over the divisor. x + 1 + What is the value of a?
grigory [225]
                    x + 1
         __________
3x+2 I 3x² +5x -3
           3x² +2x
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8 0
3 years ago
Read 2 more answers
Julie takes her kids to a playground that has the shape shown. A. While her kids are playing, Julie wants to get some exercise.
Leona [35]

Answer:

a.) Total distance Julie cover = 128 feet

b.) Total area , the playground cover = 256 ft²

Step-by-step explanation:

P. S : The exact question is -

As given,

Length of 1 side = 16 feet

As , we have

4 sides of same length

⇒ Total length of playground = 16 + 16 + 16 + 16 = 16(4) = 64 feet

a.)

As given Julie does 2 lap of the playground

⇒ Total distance Julie cover = 64 + 64 = 128 feet

b.)

As the playground has equal side, so it must be of square shape

And, we know

Area of square = (Length of one side)²

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5 0
3 years ago
Please help answer these questions. My teacher said they were really easy but I just don't understand. Will mark brainliest !!!
kodGreya [7K]

Answer:

1.  A = 59

2.  A = 43

Step-by-step explanation:

If we have a right triangle  we can use sin, cos and tan.

sin = opp/ hypotenuse

cos= adjacent/ hypotenuse

tan = opposite/ adjacent


For the first problem, we know the opposite and adjacent sides to angle A

tan A = opposite/ adjacent

tan A = 8.8 / 5.2

Take the inverse of each side

tan ^-1 tan A = tan ^-1 (8.8/5.2)

A = 59.42077313

To the nearest degree

A = 59 degrees


For the second problem, we know the  adjacent side and the hypotenuse to angle A

cos A = adjacent/hypotenuse

cos A = 15.3/21

Take the inverse of each side

cos ^-1 cos A = cos ^-1 (15.3/21)

A = 43.23323481

To the nearest degree

A = 43 degrees


6 0
3 years ago
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