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Rashid [163]
2 years ago
11

How many quarts are in 150 cups?

Mathematics
2 answers:
Fiesta28 [93]2 years ago
7 0

Answer:

37.5 quarts

Step-by-step explanation:

4 cups = 1 quart

150/4=37.5

valina [46]2 years ago
6 0

Answer:

there are 37.499999997608 quarts in 150 cups

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Each day, a restaurant chain bakes 6,777 more key lime pies than coconut cream pies. If
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Answer:

12,132

Step-by-step explanation:

It says a restaurant chain bakes 6,777 more key lime pies that cocunut cream pies. This means regardless of the amount of cream pies, the restaurant chain bakes 6,777 more.

So....

5,355+6,777 = 12,132

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3 years ago
Which of the following does NOT have a value of -5?
Contact [7]

Answer:

J. -13-18

Step-by-step explanation:

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The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

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Answer: 3  ( x + 7 )

Step-by-step explanation:

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In the number 75, 5 is the base and 7 is the exponent. Solution: False. Example 7: 4. 3 a. a a a a b. b b b. + + +. = + +. Solution:.

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