Substitute the first equation into the second equation. You will get:
4x - (2x - 5) = 7
Distribute the negative sign into the parenthesis:
4x - 2x + 5 = 7
Simplify
2x + 5 = 7
Subtract 5 on both sides
2x = 2
x = 1
Now, substitute x = 1 into the first equation:
y = 2(1) - 5
y = 2 - 5
y = -3
The solution to the system of equations is (1, -3).
<h2>
<u>Sol</u><u>ution</u><u>:</u></h2>
Equation: x² + 10x + 21
<u>Step</u><u> </u><u>1</u><u>:</u> Find two numbers that can add up to 10 and be multiplied to 21. We have: 7 & 3, in the sense that 7+3=10, and 7×3=21. Replacing 10 with 7+3, the equation is now → x² + 7x + 3x + 21
<u>Step</u><u> </u><u>2</u><u>:</u> Get the new equation bracketed → (x² + 7x) (+3x + 21)
<u>Step</u><u> </u><u>3</u><u>:</u> Use 'x' in the equation. For the first part, we have 'x'. x² = x × x so, bring out one x out side the bracket, divide 7x by = 7 → x (x +7). Do the same for the second part by dividing 21 by 3 = 7, and then bringing out 3 from the bracket → 3 (x + 7).
Bringing everything together, we have: x(x+7) +3(x+7) → (x+3) (x+7)
<h3>
<u>Final</u><u> </u><u>ans</u><u>wer</u><u>:</u></h3>
(x+3) (x+7)
<h3 />
Answer:
A
Step-by-step explanation:
You can multiply both sides on an equation by the reciprocal to cancel the fraction on the first side.
Hey!
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First Equation:
2x + 3 = -7
2x + 3 - 3 = -7 - 3 (Subtract 7 to both sides)
2x = -10
2x/2 = -10/2 (Divide 2 to both sides)
x = -5
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Second Equation:
4.5x - 7 = 20
4.5x + (-7) + 7 = 20 + 7 (Add 7 to both sides)
4.5x = 27
4.5x/4.5 = 27/4.5 (Divide 4.5 to both sides)
x = 6
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Third Equation:
-3x + 7 = 28
-3x + 7 - 7 = 28 - 7 (Subtract 7 to both sides)
-3x/-3 = 21/-3 (Divide -3 to both sides)
x = -7
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Answers:
2x + 3 = -7 → x = -5
4.5x - 7 = 20 → x = 6
-3x + 7 = 28 → x = -7
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Hope This Helped! Good Luck!