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Elodia [21]
4 years ago
13

B) the probability that the sample will contain at most 2 defective items is

Mathematics
1 answer:
leva [86]4 years ago
7 0
ExperimentSome process that occurs with well defined outcomes.OutcomeA result from a single trial of the experiment.Eventa collection of one or more outcomes.Sample SpaceA collection of all of the outcomes of an experiment.P(E)the probability of E happeningn(E)the number of elements in EProbability answers should be given as...fractions or decimalsProbability questions that ask for percent or chance should be given as...percentagesTheoretical Probability<span>What we expect the Probability of an event to be.
ie. each number on a cube should have a 1/6 probability of occurring</span>Empirical Probability<span>The Probability of an event after we run an experiment.
ie. each number on a cube should have a 1/6 probability of occurring, but we could roll a cube many times and may not get a certain number 1/6 of the time.</span>ORone or the other or both; it's ok to get just oneANDHave to get BOTHTree Diagram<span>can be drawn vertically(down) or horizontally(side ways)
*You can count the ends of the branches to get the number in the sample space(outcomes)</span>How to find the number of items when you know the probability it will occur..<span>(# of items)(Probability it will occur)
ie. If the probability a person is left handed is 1/10, how many people would you expect to be left handed in a room with 360 people?
ANSWER: (360)(1/10) = 36</span>Roster Form<span>List the elements in brackets
ie. set A is a set of all even numbers from 1-10; 
A = {2,4,6,8,10}</span>Subseta set whose elements are contained in another setComplement<span>All the elements in a set that are not in the subset
set S; S = {1,2,3,4,5,6,7,8,9,10}
subset A; A = {2,4,6,8,10}
complement of A; A' = {1,3,5,7,9}
Can be labeled with an ' OR another letter.</span>Complements Probabilities<span>If A and B are complements then P(A) + P(B) = 1
P(A) + P(A') = 1
P(A) + P(NOT A) = 1</span><span>
</span>
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marta [7]

Answer:

1=9\cdot 9+20\cdpt (-4)=81-80

Step-by-step explanation:

The greatest common divisor between 9 and 20 is 1, so we know the equation 1=9m+20n has a solution. A solution can be found either by inspection, or by applying Euclidean algorithm.

By inspection we just list some multiples of 9:

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99

and also list some mutiples of 20:

20, 40, 60, 80, 100, 120

And so we see that we can find a multiple of 9 (81) which is 1 away from a multiple of 20 (80). Which is the solution given at the start.

For the Euclidean algorithm, we should divide the greatest of the two numbers, by the smallest one, and keep track of the remainder:

20 = 9 * 2 + 2

Then we divide 9 by the remainder we got, which is 2:

9 =  2 * 4 + 1

we would continue doing this until getting a remainder of 1 (which we just did). Finally we "solve" for 1, from the last equation:

9 - 2*4 = 1

And then we solve for 2 from the first equation, and plug that in into the previous equation:

20 - 9*2 =2

9 - ( 20 - 9*2)*4 = 1

which does give us the same solution: 9\cdot 9 +20\cdot (-4)=1

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Negative one times the sum of twice a number and 3 is equal to 2 times the
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Lets just say the number is equal to x.
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