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3 years ago

What is Q=R+Rst; solve for s

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

6 0

Step-by-step explanation:

q=r+rst

Rewrite the equation as

r+rst=q

Subtract r from both sides of the equation.

r st=q−r

Divide each term by rt

(r st )/rt=(q/rt)−(r/rt)

Cancel the common factor.

(

s=(q/rt)−1/t

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2x3 + x2 + 7x - 6)-(- 2x + 10x + 10x+9)

AVprozaik [17]

Answer:

2x³ + x² - 11x - 15

Step-by-step explanation:

Step 1: Write out expression

2x³ + x² + 7x - 6 - (-2x + 10x + 10x + 9)

Step 2: Distribute negative

2x³ + x² + 7x - 6 + 2x - 10x - 10x - 9

Step 3: Combine like terms (x)

2x³ + x² + 9x - 10x - 10x - 9 - 6

2x³ + x² - x - 10x - 9 - 6

2x³ + x² - 11x - 9 - 6

Step 4: Combine like terms (constants)

2x³ + x² - 11x - 15

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3 years ago

HELP MEEE , need the right answer

Ksenya-84 [330]

Answer:

Step-by-step explanation:

We do the opposite.

3 0

2 years ago

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Function and Reasoning:

Akimi4 [234]

The number of calories per ounce of soda is 10

<h3>Part A: Represent the relationship between the number of calories and the number of ounces</h3>

The given parameters are:

Calories = 50

Ounces = 5

Let the number of calories be y and the ounces be x.

So, we have:

y = kx

Substitute y = 50 and x = 5

50 = 5k

Divide by 5

k = 10

Substitute k = 10 in y = kx

y = 10x

See attachment for the graph of the relationship between the number of calories and the number of ounces

<h3>Part B: What is the number of calories per ounce of soda?</h3>

In (a), we have:

k = 10

This means that the number of calories per ounce of soda is 10

<h3>Part C: How does the unit rate relate to the slope of the line in the graph above? </h3>

The unit rate and the slope represent the same and they have the same value

Read more about linear graphs at:

brainly.com/question/4025726

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2 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

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3 years ago

HELP QUICK PLEASE 20 POINTS

trasher [3.6K]

Answer:

-2

Step-by-step explanation:

-5n + 18

where n is the number of the term

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3 years ago

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