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vagabundo [1.1K]
3 years ago
15

Describe how you would determine whether a triangle is a right triangle given its coordinates.

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:

uhhhh

Step-by-step explanation:

A

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Khan Academy Question
Mama L [17]

Answer:

84

Step-by-step explanation:

Since we are given line OP perpendicular to line DR, then angles PDR and ODR are right angles.

Angles PDA and ADR are complementary.

Angles ODU and UDR are complementary.

Angles ADR and UDR are given as congruent.

We can conclude that angles PDA and ODU are congruent.

By AA Similarity, triangles APD and UMD are similar.

DP/DM = PA/MU

3.75/10 = 4.5/MU

3.75MU = 10 × 4.5

MU = 12 (altitude of triangle DUO)

OD = OM + MD =  4 + 10 = 14 (base of triangle DUO)

area = base × height / 2

area = 14 × 12 / 2

area = 84

4 0
1 year ago
Select the correct answer.
Scilla [17]

Answer:

B. I think

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
8 + z = 19. step equations
steposvetlana [31]

Answer:

11

Step-by-step explanation:

First subtract

19-8= Z

So solution would be

Z=11

7 0
3 years ago
Read 2 more answers
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
The sum of two.number is.24. the.sun.of the square.of the two.nunber is 306. what is the product.of the two.number
tresset_1 [31]
A) x + y = 24
B) x^2 + y^2 = 306

A) x = 24 -y
Then substituting this into B)
(24 - y)^2 +y^2 = 306
576 -48y +y^2 + y^2 = 306
2 y^2 -48y + 270 = 0
x1 = 15
x2 = 9




3 0
3 years ago
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