Answer:
61/125 or 0.488
Step-by-step explanation:
Total = 5×5×5 = 125
Numbers with no 4 = 4×4×4 = 64
Atleast one 4= 125-64 = 61
P(atleast one 4) = 61/125 or 0.488
Original position of the submarine below the Surface = -2 2/3= -8/3
Submarine at a depth of -2 2/3 feet descended by 5 1/2 feet.
So new position of the Submarine = 
To Reach the surface submarine must rise = 0-(-49/6)
As seen from the equation the two negative sign [(-)(-)] will change into a positive sign.
At the surface the position of the submarine = +49/6 feet
sin(x) = ⁴/₅
sin⁻¹[sin(x)] = sin⁻¹(⁴/₅)
x ≈ 53.13
cos(90 - x) = cos(90)cos(x) + sin(90)sin(x)
cos(90 - 53.13) = cos(90)cos(53.13) + sin(90)sin(53.13)
cos(36.87) = 0cos(53.13) + sin(53.13)
cos(36.87) = sin(53.13)
cos(36.87) = cos(90 - 53.13)
cos(36.87) = cos(36.87)
Step-by-step explanation:
3)
First, we should answer two simple questions.
1. How many ways can we travel from a-b?
2. How many ways can we travel from b-c?
This is given in the problem - because there are 7 roads connecting a to b, there are 7 ways to get from a-b. Because there are 6 roads from b-c, there are 6 ways to get from b-c.
Now that we understand this, we can use some logic to figure out the rest of the problem. Let's think about each case.
Let's go from a-b. We'll choose road 1 of 7. Now that we are in b, we have 6 more choices. This means that there are 6 ways to get to from a-c if we take road 1 when we go to b.
If we take any road going from a-b, there will be 6 options to get from b-c.
So, we can just add up the number of options because we know that there are 6 routes per road from a-b. This is simply 7*6 = 42. So, there are 42 ways to travel from a to c via b.
