An engineer on the ground is looking at the top of a building. The angle of elevation to the top of the building is 22°. The eng
ineer knows the building is 450 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?
1,114 ft
1,201 ft
1,818 ft
990 ft
2 answers:
Let the distance of the engineer from the base of the building be x, then
tan 22 = 450/x
x = 450/tan 22 = 450/0.4040 = 1,113.79
Therefore, the distance of the engineer from the base of the building to the nearest foot is 1,114 feet.
Answer:
Distance, x = 1114 ft
Step-by-step explanation:
It is given that,
The angle of elevation to the top of the building, 
Height of the building, h = 450 ft
We have to find the distance from the engineer to the base of the building i.e. x
In triangle ABC, using trigonometric equations as :




or
x = 1114 ft
So, the distance from the engineer to the base of the building is option (A) i.e. 1114 ft
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