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Artist 52 [7]
3 years ago
9

Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv

en circle is also equal.
Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

\Delta Sector=\dfrac{1}{2}r^2\theta

Whereas the area of a circle for a radius r is given as

\Delta Circle=\pi r^2

Now the ratio is given as

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

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The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

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The function which has range (2, infinity) from the provided function is y = 5ˣ +2. Option 4 is correct.

<h3>What is range of function?</h3>

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The first function given in the problem is,

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