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Neporo4naja [7]
3 years ago
8

How to do the problem step by step because I do not know how to do it

Chemistry
1 answer:
antoniya [11.8K]3 years ago
8 0
I believe it's ;

 <span>one truck load is 2.5*1.5*1 = 3.75m^3 </span>

<span>7/3.75 = 1.86 loads, </span>
<span>so 2 trips must be made.

Hope this helped! :)</span>
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Match the image with the correct invention
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1. Watt stream engine

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3. Fulton steamboat

These are the correct answers.

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3 years ago
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Are the particles moving faster or slower as time goes on? (Diagram F)
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A compound with a molar mass of 102.133 g/mol contains an element with a subscript of 5 . the element is 58.80 g per 100.0 g com
VLD [36.1K]

Answer:

12.0108408

Explanation:

Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.

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6 0
4 years ago
For the reaction
ddd [48]

Answer:

52.2 g

Explanation:

Step 1: Write the balanced equation

3 KOH + H₃PO₄ ⟶ K₃PO₄ + 3 H₂O

Step 2: Calculate the moles corresponding to 89.7 g of KOH

The molar mass of KOH is 56.11 g/mol.

89.7 g × 1 mol/56.11 g = 1.60 mol

Step 3: Calculate the moles of H₃PO₄ needed to react with 1.60 moles of KOH

The molar ratio of KOH to H₃PO₄ is 3:1. The moles of H₃PO₄ needed are 1/3 × 1.60 mol = 0.533 mol.

Step 4: Calculate the mass corresponding to 0.533 moles of H₃PO₄

The molar mass of H₃PO₄ is 97.99 g/mol.

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3 0
3 years ago
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geniusboy [140]

Answer:

to the right (products side)

Explanation:

The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:

a A + b B → c C + d D

The equilibrium constant expression is:

K = \frac{[C]^{c} [D]^{d}  }{[A]^{a} [B]^{b}  }

A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).

Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.

Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.

5 0
3 years ago
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