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balu736 [363]
3 years ago
5

How could gamma rays,for example change something irreversibly

Chemistry
2 answers:
ANTONII [103]3 years ago
6 0


compute the average rate of change of the function f(x)=(the square root of)4x+8 as it moves from x1=-2 to x2=7
coldgirl [10]3 years ago
5 0
They emit radiation. Which can be very harmful to living things, as well as some non living things. I hope i answered you question :)
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Carbon dioxide is released into the atmosphere by _____.
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Answer:

4 a minor but very important component of the atmosphere corban dioxide is released through natural processes such as reputation.;

Explanation:

a minor but very important component of the atmosphere corban dioxide is released through natural processes such as reputation

3 0
2 years ago
Will give most brainly.
Anna [14]

Answer:

One mole

Explanation:

It tells u the concentration

8 0
2 years ago
The heisenberg uncertainty principle status that
Juli2301 [7.4K]
The Heisenberg uncertainty principle listed above states that it’s impossible to determine with high precision both the momentum and position of an electron simultaneously.
8 0
2 years ago
How many moles are in 4.01x10^24 particles?
skelet666 [1.2K]

Answer:

6.64

Explanation:

so moles

\frac{number  \: of \: \: particles \: }{6.02 \times  {10}^{23} }

then do =4.01×10^24/6.02×10^23

you get the answer as 6.6445 u only need to write the answer to

3.S.F 6.64 moles

hope this make sense :)

6 0
3 years ago
If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol
Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity  :

v_{rms}=\sqrt{\frac{3RT}{M}}

K.E_{avg}=\frac{3}{2}RT

K.E =\frac{1}{2}mv_{rms}^{2}

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

K.E_{avg}=\frac{3}{2}RT

T=\frac{2(K.E)}{3(R)}

K.E of He = 4310 J/mol

T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}

T=345.60K

<u>Now , Use Vrms to calculate the velocity of O2</u>

v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}

v_{rms}=\sqrt{\frac{8619.9552}{0.032}}

v_{rms}=\sqrt{26935.001}

v_{rms}=519.01m/s

6 0
3 years ago
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