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Kisachek [45]
3 years ago
15

Please help.

Chemistry
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

9429.9

Explanation:

periodt

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Svet_ta [14]
Yes of course!!!! :)
5 0
3 years ago
What is the formula of the chromium(iii) complex that contains two ammonia and four thiocyanate (scn−) ligands?
Nonamiya [84]
Answer is: formula of the complex is [Cr(NH₃)₂(SCN)₄<span>]</span>⁻<span>.
This complex has negative charge (-1) because chromium (central atom or metal) has oxidation number +3, first ligand ammonia has neutral charge and second ligand thiocyanate has negative oxidation number -1:
+3 + 2</span>·0 + 4·(-1) = -1.
4 0
3 years ago
The heaviest element to be created by exothermic nuclear fusion is:
Lunna [17]

Answer:

The heaviest element to be created by exothermic nuclear fusion is Iron

Explanation:

Because it is the heaviest element produced during fusion without having to add energy, and it is the lightest element produced during fission without having to add energy. Energy-wise, everything in the universe wants to be iron! Iron is the most abundant element on Earth, making up 34.5 percent of Earth's mass.

8 0
2 years ago
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if a glass jar has a density of 2.58 g/ml and has a mass of 6.8 g, what is its volume? (round to the ones place.)
Naya [18.7K]

Answer:

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Explanation:

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3 0
2 years ago
At what temperature, would the volume of a gas
PtichkaEL [24]

Explanation:

P1V1 = nRT1

P2V2 = nRT2

Divide one by the other:

P1V1/P2V2 = nRT1/nRT2

From which:

P1V1/P2V2 = T1/T2

(Or P1V1 = P2V2 under isothermal conditions)

Inverting and isolating T2 (final temp)

(P2V2/P1V1)T1 = T2 (Temp in K).

Now P1/P2 = 1

V1/V2 = 1/2

T1 = 273 K, the initial temp.

Therefore, inserting these values into above:

2 x 273 K = T2 = 546 K, or 273 C.

Thus, increasing the temperature to 273 C from 0C doubles its volume, assuming ideal gas behaviour. This result could have been inferred from the fact that the the volume vs temperature line above the boiling temperature of the gas would theoretically have passed through the origin (0 K) which means that a doubling of temperature at any temperature above the bp of the gas, doubles the volume.

From the ideal gas equation:

V = nRT/P or at constant pressure:

V = kT where the constant k = nR/P. Therefore, theoretically, at 0 K the volume is zero. Of course, in practice that would not happen since a very small percentage of the volume would be taken up by the solidified gas.

8 0
3 years ago
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