The answer to this problem is neither. To find this you would just plug in each ordered pair into the equation for the x and y values. Then you would compare if they are equal
2/5m - 4/5 - 3/5m...combine like terms
-1/5m - 4/5
<span>(2^1/2x2^3/4)^2
</span><span> ((2^1/2)(2^3/4))^2
</span> ((2^1/2)^2)((2^3/4)^2)
(2)(2^3/2)
(4*2^3)^(1/2)
(2*2*2^3)^(1/2)
(*2^5/2)
The answer for this case is
b. <span>sqrt 2^5</span>
Answer:
Step-by-step explanation:
Answer:
11/12
Step-by-step explanation:
5/4 ---- 15/12
1/3------ 4/12
11/12
