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3 years ago

A,b,c or d? Please help

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

3 0

C
Mathy49 See you later lol deleted my old one cuz it's in spanish

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X^5(1-x)^6<br> How to find the critical points

Lana71 [14]

$y=x^5(1-x)^6\\
y'=5x^4(1-x)^6+x^5\cdot6(1-x)^5\cdot(-1)\\
y'=x^4(1-x)^5(5(1-x)-6x)\\
y'=x^4(1-x)^5(5-5x-6x)\\
y'=x^4(1-x)^5(5-11x)\\\\
x^4(1-x)^5(5-11x)=0\\
\boxed{x=0 \vee x=1 \vee x=\dfrac{5}{11}}$

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3 years ago

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Simplify this expression: a + 2a + 3b - a - b

aniked [119]

Simplified would be 2a+2b

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3 years ago

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What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago

The area of a rectangular field is 8342 yd2 . if the width of the field is 86 yards, what is its length?

Irina18 [472]

97yards...............................................................................................................................................................................................................................................................................................................

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3 years ago

Quanto é 60 x 11 + 346²

Bond [772]

Answer:

120376

Step-by-step explanation:

Primeiro peguei 60x11 e os multipliquei e obtive 660. Em seguida, descobri que 346 ^ 2 é 119716. Somei meus dois números e obtive 120376.

Espero que isso ajude você! :)

8 0

3 years ago