Answer:
Only option B is correct, i.e. all real values of x except x = 2.
Step-by-step explanation:
Given the functions are C(x) = 5/(x-2) and D(x) = (x+3)
Finding (C·D)(x) :-
(C·D)(x) = C(x) * D(x)
(C·D)(x) = 5/(x-2) * (x+3)
(C·D)(x) = 5(x+3) / (x-2)
(C·D)(x) = (5x+15) / (x-2)
Let y(x) = (C·D)(x) = (5x+15) / (x-2)
According to definition of functions, the rational functions are defined for all Real values except the one at which denominator is zero.
It means domain will be all Real values except (x-2)≠0 or x≠2.
Hence, only option B is correct, i.e. all real values of x except x = 2.
Subtract 17 from both sides
9= -d+17
9 - 17 = -d + 17 - 17
-8 = -d
Then divide.
-8/1 = -d-1
Cancel terms that are in both numerator and denominator
Answer:
8 = d
Answer:
-9＞x
Step-by-step explanation:
5(x+4)＞2x-7
5x+20＞2x-7
5x+20＞2x-7
<u> +7 +7</u>
5x+27＞2x
↓
5x+27＞2x
<u>-5x -5x</u>
27＞-3x
↓
<u>27＞-3x </u>
-3 -3
= -9＞x
The answers is 11x+2 I’m pretty sure. I can’t tell if your x3 was an exponent or multiplying.
Answer: If solving for P it is p = -3/5
If you are just wanting the equation it is 5p+3
Step-by-step explanation: Plug in c and d into 5p+cd
You get 5p+(1/5)(15)
Once done with the math it is 5p+3
