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3 years ago

14

How many possible outcomes are there when flipping a coin 9 times?

1 answer:

otez555 [7]3 years ago

3 0

Each time the coin is tossed, there are two possible outcomes. The total number of possible outcomes when 9 tosses are made is given by:
$2^{9}=512\ outcomes$

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Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

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9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

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<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

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$i \times \sqrt{ {2}^{2} \times 2 }$

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<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

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<h2> $4. \: \sqrt{ - 75}$ </h2>

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<h2> $5. \: \sqrt{ - 72}$ </h2>

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$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

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<h2> $6. \sqrt{ - 20}$ </h2>

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<h2> $7. \: \sqrt{ - 27}$ </h2>

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<h2> $8. \: \sqrt{ - 12}$ </h2>

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<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

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<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

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Step-by-step explanation:

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