Answer:
the first one is the answer y = (x-2)^2 + 1
Step-by-step explanation:
The vertex form of a quadratic function is y = a(x – h)^2 + k, where a, h, and k are constants. h and k are vertex.
vertex is (2,1) which is (h,k)
passes through (0,5)
Equation is y = a( x - 2)^2 + 1 . now substituting (0,5) in for x and f(x),
5 = a ( 0 - 2) ^2 + 1 and solve for a.....
5 = 4a + 1
5-1 = 4a
4a = 4.......... a = 1
equation becomes y = 1(x-2)^2 + 1 or y= (x-2)^2 + 1
