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Aneli [31]
3 years ago
14

To round 56.487 to the nearest tenth, you find the digit in the what place?

Mathematics
1 answer:
sveta [45]3 years ago
4 0

Answer:

56.5

Step-by-step explanation:

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Given the equation 2Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.
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For what values of b is f(x) = b^x an increasing function? 
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In the figure shown, which pair of angles must be supplementary
lana [24]

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PQT and TQS

Step-by-step explanation:

they must supplement each other to get the 90

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2 years ago
Solve 480 divibed by 8
Thepotemich [5.8K]
480 divided by 8 is 60
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How do you do this math
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Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

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