$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$

$\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM$

Hence there is no such natural numbers exist.

7 0

3 years ago

PLEASE HELP PLEASE I WILL GIVE 20 POINTS AND BRAINLIEST The club will base its decision about whether to increase the budget for

iren2701 [21]

Answer:

They should in crease budget.

Step-by-step explanation:

divide each number by 2 to see how often they go equally/use the data table you have available of the two climbers.

5 0

3 years ago