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3 years ago

Which of the point-slope equations below are correct for the line that passes through points (-4,-14) and (1,3)?

1 answer:

4 0

(-4,-4)(1,3)
slope = (3 - (-4) / (1 - (-4)
slope = (3 + 4) / (1 + 4) = 7/5

y - y1 = m(x - x1)...using (-4,-4)
slope(m) = 7/5
y - (-4) = 7/5(x - (-4) =
y + 4 = 7/5(x + 4) <==here is one

y - y1 = m(x - x1)..using (1,3)
slope = 7/5
y - 3 = 7/5(x - 1) <== here is the other one

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2 years ago

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The answer is " $0.90>p>0.75.$ "

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$\text{Cinnabar vestigial} \ \ \ \ \ \ \ \ \ \ \ 384 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \ -6 36 \ \ \ \ \ \ \ \ \ \ \ 0.092308\\\\$

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$vestigial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 32 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.257143\\\\$

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$\text{cinnabar} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.8 \\\\$

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Eight phenotypes were present.

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$\to df = 8-1= 7$

For p-value 0,9, Chi-square is 2.83;

The p-value of 0.75 is 4.5. Chi-square

Chi-sqaure value is observed at 2.965.

That means 0.90>p-value>0.75.

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3 years ago