Answer:
The sum of all the sides to this quadrilateral will equal a total of 20 inches, so you set up the equation:
2 + 2x + 7 + x + 2 = 20
Solve for x by combining like terms;
(2 + 7 + 2) + (2x + x) = 20
Which simplifies to;
11 + 3x = 20
Get rid of constants;
-11 -11
3x = 9
Isolate x by getting rid of it's coefficient;
/3 /3
<u>x = 3</u>
Now, to find the length of PQ, we plug in the value of x(3) into the equation that contains the line PQ.
x + 2
<u>3</u> + 2
= <u>5 inches.</u>
Now, to find the length of RS, we plug in the value of x(3) into the equation that contains the line RS.
2x
2(3)
= <u>6 inches.</u>
Answer:
I'm going to guess that it is January 3rd. Happy birthday, late or early, by the way! :)
Step-by-step explanation:
To convert mi/h to ft/sec, multiply it to 1.466.
So 3.4 mi/h x 1.466 = 4.986 ft/sec
<span>2 ^1/2
8 ^1/3 = (2³)^1/3 = 2
12 ^1/4
15 ^1/5
</span>
![\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides} \\\\\\ tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)](https://tex.z-dn.net/?f=%5Cbf%20tan%28x%5Eo%29%3D1.11%5Cimpliedby%20%5Ctextit%7Btaking%20%7Dtan%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28x%5Eo%29%5D%3Dtan%5E%7B-1%7D%281.11%29%5Cimplies%20%5Cmeasuredangle%20x%3Dtan%5E%7B-1%7D%281.11%29)
plug that in your calculator, make sure the calculator is in Degree mode
