Answer:
Linear
Step-by-step explanation:
There are no reapeting x values.
The value of x is 1.14 or x = -1.47
We find the value of x in the quadratic equation 3x^2 +x-5=0
Using the formula: (-b ± √ (b²- 4 a c)) / (2a)
Where the value of a = 3, b = 1 and c = -5
Substituting the above values (a = 3, b = 1 and c = -5)
in the formula:
(-1 ± √ (1²- 4 3 (-5))) / (2*3)
= (-1 ± √ (1+60)) / (6)
= (-1 ± √ (61)) / (6)
= (-1 ± 7.81) / (6)
= (-1 + 7.81) / (6) or (-1 -7.81) / (6)
= (6.81) / (6) or (-8.81) / (6)
=1.135 or -1.468
Hence the value of x= 1.14 or -1.47
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not enough information to solve it as there are two unknowns in one inequality
We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
So our initial population is again 15, and P = i•e^rt
P = 15•e^(.693×11) = 15•e^(7.624)
P = 15•2046.94 = 30,704
14 cause shes only getting 1 pet and there are 14 animals in total
