The last one D. is the answer
Answer:
Answer is d
Step-by-step explanation:
- A computer programmer has a 35 change of finding a bug in any given program.
- we have to find probability that she finds a bug within the first 3 programs she examines
- success = 0.35, failure = 0.65
- She get a bug in the first program itself
- p = 0.35
- She get a bug in 2nd program
- q = 0.65×0.35 =0.2275
- She get a bug in the 3rd program
- r = 0.65×0.65×0.35
- r = 0.147875
- Add all the three probabilities for answer
- P = p+q+r
- P = 0.35+0.2275+0.147875
- P = 0.725375
- P = 0.73
- The probability of the answer is 0.73
Total outcome is 50 [because the number produced by the machine is from 1 to 50]
Question a:
Multiple of 10 are 10, 20, 30, 40, 50
There are five possible outcomes for multiple of 10
P(Multiple of 10) = 5/50 = 1/10
Question b:
Number 1 to 50 will be all the outcomes that are not 100
There are 50 possible outcomes
P(not 100) = 50/50 = 1
Question c:
Multiple of 4 that are less than 50 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48
There are 12 possible outcomes for multiple of 4
We want 'not multiple of 4' so we need to do 50 - 12 = 38 outcomes
P(not a multiple of 4) = 38/50 = 19/25
Question d:
One digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9
There are 9 possible outcomes
P(one-digit number) = 9/50
Add up all the money for college and the note books ect then you have your answer
I believe that you are supposed to use Lower Case Roman Numerals
