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3 years ago

a watch is getting slow by 2 minutes for each hour in a day . if it shows 10 am now. what shall be the time after 12hours

Mathematics

2 answers:

Marizza181 [45]3 years ago

8 0

12*2=24

10:00+12:00-0:24=<u>21:36</u>

Assoli18 [71]3 years ago

7 0

Answer:

9:36 p.m.

Step-by-step explanation:

10 am + 12 hours = 10:00 pm

2 minutes every hour

12 hours x 2 = 24 minutes

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the sum of 2 numbers is 7 the larger number is 16 more than 2 times the smaller number what are the numbers

EastWind [94]

Answer:

x=larger no

y= smaller no

Step-by-step explanation:

x+y=7--------(1)

x=16 + 2y------(2)

(2)--->(1)

16+2y+y = 7

3y + 16 = 7

3y = -9

y = -3//

so x=10

7 0

3 years ago

Read 2 more answers

Evaluate 3x + 7 for x = 5.

suter [353]

Answer:

Step-by-step explanation:

If x = 5, then plug 5 in for x .

3(5) + 7

15 + 7 = 22

6 0

3 years ago

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suppose that unit price p in dollars for a quantity demanded X of a certain product of a company is given by p=-0.08+620 (0 <

77julia77 [94]

I am sorry, I would love to help but I am not sure. Good luck anyways. :(

7 0

3 years ago

The client is to receive cyclophosphamide (Cytoxan) 50 mg/kg intravenously in divided doses over 5 days. The client weighs 176 p

marishachu [46]

Answer:

800 mg

Step-by-step explanation:

As the excerpt states that the client weights 176 pounds and is to receive cyclophosphamide (Cytoxan) 50 mg/kg, we have to convert 176 pounds to kg:

1 kg → 2.20 pounds

x ← 176 pounds

x= (176 pounds * 1 kg)/2.20 pounds= 80 kg

Now, we have to determine the total amount of cyclophosphamide (Cytoxan) that the client has to receive:

50 mg/kg

For 80 kg: 80 kg *50 mg/kg= 4,000 mg

As the dose is divided over 5 days:

4,000 mg / 5= 800 mg

The client will receive 800 mg of cyclophosphamide each day.

6 0

3 years ago

How do I solve this out??

GuDViN [60]

<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

$\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]$

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

$\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]$

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0

2 years ago