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1 year ago

If f(x) and its inverse function, fx), are both plotted on the same coordinate plane, what is their point of intersection?

Mathematics

1 answer:

Lubov Fominskaja [6]1 year ago

7 0

Answer: (3, 3)

Step-by-step explanation:

the graphs of $f$ and $f^{-1$ are flipped: if the point $(x, y)$ is on the graph of $f$ , then the point $(y, x)$ is on the graph of $f^{-1$ .

Any points of intersection will satisfy $(x, y) = (y, x)$ . A point that satisfies this property must have the same x and y coordinate. (Think about it.) The only point on $f$ like that is $(3, 3)$ , so that is the point of intersection.

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What is the pattern in this sequence?

Sladkaya [172]

Answer in #1 it ads up by 8

5 0

2 years ago

Read 2 more answers

assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the

drek231 [11]

Answer:

65.3658 inches

Step-by-step explanation:

Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value $x_{0}$ such that $P(X < x_{0}) = 0.76$ , but, $0.76 = P(X < x_{0}) = P((X-63.6)/2.5 < (x_{0}-63.6)/2.5) = P(Z < (x_{0}-63.6)/2.5)$ , i.e., $(x_{0}-63.6)/2.5$ is the 76th percentile of the standard normal distribution. So, $(x_{0}-63.6)/2.5 = 0.7063$ , $x_{0} =63.6+(2.5)(0.7063) = 65.3658$ . Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.

7 0

3 years ago

Can someone help me pls

VLD [36.1K]

Answer:

-12

Step-by-step explanation:

Since a = -6,we have to multiply 2 and -6,and you get -12 bc we have to put the sign of the bigger digit which is -6 in this problem,so you have to write -12

4 0

2 years ago

Ronald measured a house and its lot and made a scale drawing. The front patio, which is 14 meters wide in real life, is 7 millim

zhannawk [14.2K]

Answer:

2 metre= 1millimetre

Step-by-step explanation:

From the measurement of the house The front patio, is 14 meters wide in real life, is 7 millimeters wide in the drawing

Real life= 14 meters

Drawing= 7 millimeters,

The scale he used is 2 metre= 1millimetre

Which means he magnify the drawing by scale of 2 metre to get the real life structure.

✓Let us clarify it

14 meters = 7 millimeters

2 metre= x millimeter

If we cross multiply

7 millimeters× 2 metre= 14 metre × X millimeters

Make X subject of the formula we have

X= 1millimetres

3 0

2 years ago

Need help with 35 thank you so much!!

Yakvenalex [24]

If a pentagon is regular, then all of the sides are the same length. This means that

$5x-4=2x+11 \iff 5x-2x = 11+4 \iff 3x=15 \iff x = 5$

So, if $x=5$ , the lengths of the sides evaluate to

$5x-4 = 25-4=21,\quad 2x+11=10+11=21$

So, all the sides of the pentagon are 21 units long, and AB is 21 units long as well, because all sides are the same length.

3 0

2 years ago