Horizontal component of force = 100cos(36)= 80.9 N
Explanation:
Newton’s First Law of Motion - if an object is at rest, it takes un-
balanced forces to make it move. Conversely, if an object is moving
it takes an unbalanced force to make it change it’s direction or speed.
Newton was the first to see that such apparently diverse phenomena as a satellite moving near the Earth's surface and the planets orbiting the Sun operate by the same principle: Force equals mass multiplied by acceleration, or F=ma.
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Answer:
The energies corresponding to each of the allowed orbitals are called energy levels.
Explanation:
A scientist known as Niels Bohr put forward that electrons in an atom covers some permitted orbitals with a specific energy. In other words, the energy of an electron in an atom is not continuous, but 'quantized.' The energies corresponding to each of the allowed orbitals are called energy levels.
![E = -\frac{E_0}{n^2} \\where \\E_0 = 13.6 eV (1 eV = 1.602\times 10^{-19}Joules)\\and\ n = 1,2,3...](https://tex.z-dn.net/?f=E%20%3D%20-%5Cfrac%7BE_0%7D%7Bn%5E2%7D%20%5C%5Cwhere%20%5C%5CE_0%20%3D%2013.6%20eV%20%281%20eV%20%3D%201.602%5Ctimes%2010%5E%7B-19%7DJoules%29%5C%5Cand%5C%20n%20%3D%201%2C2%2C3...)
Answer:
![m=1.01\times 10^6\ kg](https://tex.z-dn.net/?f=m%3D1.01%5Ctimes%2010%5E6%5C%20kg)
Explanation:
Given that,
Pressure, P = 1 atm = 101325 Pa
Area of the square surface, A = 10² = 100 m²
We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,
![P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7Bmg%7D%7BA%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7BPA%7D%7Bg%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7B101325%5Ctimes%2010%5E2%7D%7B10%7D%5C%5C%5C%5Cm%3D1.01%5Ctimes%2010%5E6%5C%20kg)
So, the required mass of the vertical column of air is
.
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.
The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.
v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s
Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.
The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.
Combining this together we get:
(1) vx=40m/s and vy=10m/s