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3 years ago

13

Is it possible for a baseball to have as large a momentum as a much more massive bowling ball

1 answer:

kirza4 [7]3 years ago

8 0

Yes it is possible. Momentum is calculated by the mass of the object times its velocity.
For example, say a bowling ball weighs 3.0kg and is travelling at a speed of 3.0m/s. Its momentum would be 3.0×3.0=9.0 kg·m/s.
Now say we have a baseball weighing 0.20kg and it is travelling at a speed of 47.0m/s. Its momentum would be 0.20×47.0=9.4 kg·m/s, which is more than that of the bowling ball.

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Psy 325 has anyone had this course

Pavlova-9 [17]

I do not have that one but i think you can download that in the internet.

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3 years ago

During one cycle, a refrigerator removes 500 J from a cold reservoir and discharges 800 J to its hot reservoir. (a) What is its

Paraphin [41]

Answer:

a)COP = 1.67

b) W = 300 J

Explanation:

given,

refrigerator removes = 500 J from a cold reservoir

discharge = 800 J to its hot reservoir

a) COP = $\dfrac{Q}{w}$

COP = $\dfrac{500}{800-500}$

COP = 1.67

b) heat per cycle exhausted to the

W + 500 = 800

W = 800- 500

W = 300 J

5 0

3 years ago

A whistle of frequency 564 Hz moves in a circle of radius 71.2 cm at an angular speed of 17.1 rad/s. What are (a) the lowest and

trapecia [35]

Answer:

a) $f'=544.66 \textup{Hz}$

b) $f'=584.75 \textup{Hz}$

Explanation:

Given:

Frequency of the whistle, f = 564 Hz

Radius of the circle, r = 71.2 cm = 0.712 m

Angular speed, ω = 17.1 rad/s

speed of source, $v_s$ = rω = 0.712 × 17.1 = 12.1752 m/s

speed of sound, v = 343 m/s

Now, applying the Doppler's effect formula, we have

$f'=f\frac{v\pm v_d}{v\pm v_s}$

where,

$v_d$ = relative speed of the detector with respect to medium = 0

a) for lowest frequency, we have the formula as:

$f'=f\frac{v}{v+v_s}$

on substituting the values, we get

$f'=564\times\frac{343}{343+12.1752}$

or

$f'=544.66 \textup{Hz}$

b) for maximum frequency, we have the formula as:

$f'=f\frac{v}{v-v_s}$

on substituting the values, we get

$f'=564\times\frac{343}{343-12.1752}$

or

$f'=584.75 \textup{Hz}$

3 0

3 years ago

A 16.0 m long, thin, uniform metal rod slides north at a speed of 21.0 m/s. The length of the rod maintains an east-west orienta

Gekata [30.6K]

Answer:

14.112 mV

Explanation:

L = 16 m, v = 21 m/s, B = 42 μ T = 42 x 10^-6 T

The formula for the induced emf is given by

e = B x v x L

e = 42 x 10^-6 x 21 x 16 = 14.112 x 10^-3 V = 14.112 mV

Thus, the induce emf is 14.112 mV.

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3 years ago

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astraxan [27]

Answer:

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3 years ago