1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
miss Akunina [59]
3 years ago
13

If your

Physics
2 answers:
Oxana [17]3 years ago
4 0
What are you asking?
tamaranim1 [39]3 years ago
3 0
This answer is a because if you prepare earlier for good health it will help you stay healthier
You might be interested in
An unknown galaxy has a large flattened core. Which of the following classifications would best fit this galaxy's description? I
Alja [10]

Answer:

Spiral

i know it is so dont say nun people

Explanation:

7 0
3 years ago
Read 2 more answers
A man is standing on a weighing machine on a ship which is bobbing up and down with simple harmonic motion of period T=15.0s.Ass
STALIN [3.7K]

Well, first of all, one who is sufficiently educated to deal with solving
this exercise is also sufficiently well informed to know that a weighing
machine, or "scale", should not be calibrated in units of "kg" ... a unit
of mass, not force.  We know that the man's mass doesn't change,
and the spectre of a readout in kg that is oscillating is totally bogus.

If the mass of the man standing on the weighing machine is 60kg, then
on level, dry land on Earth, or on the deck of a ship in calm seas on Earth,
the weighing machine will display his weight as  588 newtons  or as 
132.3 pounds.  That's also the reading as the deck of the ship executes
simple harmonic motion, at the points where the vertical acceleration is zero.

If the deck of the ship is bobbing vertically in simple harmonic motion with
amplitude of M and period of 15 sec, then its vertical position is 

                                     y(t) = y₀ + M sin(2π t/15) .

The vertical speed of the deck is     y'(t) = M (2π/15) cos(2π t/15)

and its vertical acceleration is          y''(t) = - (2πM/15) (2π/15) sin(2π t/15)

                                                                = - (4 π² M / 15²)  sin(2π t/15)

                                                                = - 0.1755 M sin(2π t/15) .

There's the important number ... the  0.1755 M.
That's the peak acceleration.
From here, the problem is a piece-o-cake.

The net vertical force on the intrepid sailor ... the guy standing on the
bathroom scale out on the deck of the ship that's "bobbing" on the
high seas ... is (the force of gravity) + (the force causing him to 'bob'
harmonically with peak acceleration of  0.1755 x amplitude).

At the instant of peak acceleration, the weighing machine thinks that
the load upon it is a mass of  65kg, when in reality it's only  60kg.
The weight of 60kg = 588 newtons.
The weight of 65kg = 637 newtons.
The scale has to push on him with an extra (637 - 588) = 49 newtons
in order to accelerate him faster than gravity.

Now I'm going to wave my hands in the air a bit:

Apparent weight = (apparent mass) x (real acceleration of gravity)

(Apparent mass) = (65/60) = 1.08333 x real mass.

Apparent 'gravity' = 1.08333 x real acceleration of gravity.

The increase ... the 0.08333 ... is the 'extra' acceleration that's due to
the bobbing of the deck.

                        0.08333 G  =  0.1755 M

The 'M' is what we need to find.

Divide each side by  0.1755 :          M = (0.08333 / 0.1755) G

'G' = 9.0 m/s²
                                       M = (0.08333 / 0.1755) (9.8) =  4.65 meters .

That result fills me with an overwhelming sense of no-confidence.
But I'm in my office, supposedly working, so I must leave it to others
to analyze my work and point out its many flaws.
In any case, my conscience is clear ... I do feel that I've put in a good
5-points-worth of work on this problem, even if the answer is wrong .

8 0
3 years ago
8750 J of heat are applied to a piece of aluminium causing a 56C increase in its
vitfil [10]

Answer:146.8983 grams

5 0
3 years ago
A particle moving in the x direction is being acted upon by a net force f(x)=cx2, for some constant
makkiz [27]
The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
\Delta K = W
The work done on the particle is the integral of the force on dx:
W= \int\limits^{3L}_L {F(x)} \, dx = \int\limits^{3L}_L {cx^2} \, dx = \frac{26}{3}cL^3
So, this corresponds to the change in kinetic energy of the particle.
6 0
3 years ago
When you shock your self because of a door knob this is an example of
Anna007 [38]

Answer:

C

Explanation:

Static electricity is what makes your hair stand up when you rub a balloon against it or gives you a shock from your doorknob. In static electricity, electrons are moved around mechanically (i.e. by someone rubbing two things together).

HOPE THIS HELPED AND LETTER D MADE ME LAUGH

8 0
3 years ago
Read 2 more answers
Other questions:
  • Which statement is true about voice?
    8·2 answers
  • What is your understanding of repetition and replication in science?
    11·1 answer
  • What is the Ring of Fire?
    5·2 answers
  • A string tied between two post is oscillating at 3Hz. A student determines the standing waves have a length of 4 meters. What is
    9·1 answer
  • A pendulum clock is taken to the moon (g = 1.6 N/kg). How long must the pendulum be in order for the clock to
    5·1 answer
  • Which kinds of objects emit light? A. objects that shine B. hot objects C. distant objects D. colored objects E. all objects
    15·2 answers
  • A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the centripetal
    15·1 answer
  • If the archerfish spits its water 30 degrees from the horizontal aiming at an insect 1.2 m above the surface of the water, how f
    12·1 answer
  • 1. Describe the components of the reflex arc
    8·1 answer
  • HELP ME ASAP PLEASE!!!!!
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!